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[#32] 2 Min. Challenge: Device

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Praetorian
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[#32] 2 Min. Challenge: Device [#permalink] New post   26 Mar 2004, 17:30
138

1. Time yourself
2. Solve as fast as you can
3. Write down your solution here ,and your time

Mr. P, a mechanical engineer, has made three devices which he claims can reduce fuel consumption in cars by 25%, 30% and 45%, respectively. Mr. G buys these three devices and fits them into his car. The exact saving of fuel consumption will work out to (given that the three devices are independent in effect)

a. 100%
b. 71.125%
c. 65.25%
d. 75%
e. 80%



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Re: [#32] 2 Min. Challenge: Device [#permalink] New post   26 Mar 2004, 17:44
My ans: b
Time = 3 mins
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Paul
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Re: [#32] 2 Min. Challenge: Device [#permalink] New post   26 Mar 2004, 19:28
B) between 2-3 min.
1 - .75*.7*.55 = .71125
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Re: [#32] 2 Min. Challenge: Device [#permalink] New post   27 Mar 2004, 02:00
In accord with PAUL, Answer should be: 71.125% (B)

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Re: [#32] 2 Min. Challenge: Device [#permalink] New post   27 Mar 2004, 08:06
praetorian123 wrote:
138

1. Time yourself
2. Solve as fast as you can
3. Write down your solution here ,and your time

Mr. P, a mechanical engineer, has made three devices which he claims can reduce fuel consumption in cars by 25%, 30% and 45%, respectively. Mr. G buys these three devices and fits them into his car. The exact saving of fuel consumption will work out to (given that the three devices are independent in effect)

a. 100%
b. 71.125%
c. 65.25%
d. 75%
e. 80%


Let us assume, before using the given three devices,
four-wheelers take X unit fuel.
By using all the three devices, fuel consumption will
reduced to

= X * (100тАУ25)* (100тАУ30)*(100тАУ45)
................................
100* 100 * 100
= 0.28875 X

Hence, percentage saving in fuel consumption

X - 0.28875X * 100 = 71.125%
................
X



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Re: [#32] 2 Min. Challenge: Device [#permalink]
27 Mar 2004, 08:06
Moderator:
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