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Re: 5 roots in one equation [#permalink]
Do we really need to know till power of 2?? not even 3?
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Re: 5 roots in one equation [#permalink]
testprep2010 wrote:
(x-a)(x-b)(x-c)(x-d)(x-e)
= x^5
- (a+b+c+d+e) x^4 --[one at a time]
+ (ab+ac+ad+ae+bc+db+be+cd+ce+de...2 at a time) x^3
- (abc+acd+ade+bcd+bce+cde...3 at a time) x^2
+ (abcd+acde+abde+...4 at a time) x
- abcde

x5 − 5x^4 + kx^3 + mx^2 + nx − 1 = 0

How to find sum of products of 2 roots taken at a time ? k

How to find sum of products of 3 roots taken at a time ? -m


Hope this helps!


Good explanation. Kudo given.



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Re: 5 roots in one equation [#permalink]
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