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A call center has two teams. Each member of Team A was able

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actleader
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A call center has two teams. Each member of Team A was able [#permalink] New post   Updated on: 30 Oct 2012, 22:25
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A call center has two teams. Each member of Team A was able to process 4/5 calls as compared to each member of Team B. If Team A has 5/8 as many number of call center agents as Team B, what fraction of the total calls was processed by Team B?

A. 3/2
B. 3/4
C. 2/3
D. 1/2
E. 1/5
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C

Originally posted by actleader on 30 Oct 2012, 12:48.
Last edited by Bunuel on 30 Oct 2012, 22:25, edited 2 times in total.
Edited the question and the tags.
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Re: A call center has two teams. Each member of Team A was able [#permalink] New post   30 Oct 2012, 13:20
what is the source of this question ??

is not a proprer gmat like question because gmat use the brackets [ ] only if a number could be rounded to the next number i.e. : if [x] is 1.5 and x is rounded to the lower less than X what is X : 1 is X, i remember 1 or max 2 problems of this genere in the entire OG )

;)
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Re: A call center has two teams. Each member of Team A was able [#permalink] New post   30 Oct 2012, 22:32
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actleader wrote:
A call center has two teams. Each member of Team A was able to process 4/5 calls as compared to each member of Team B. If Team A has 5/8 as many number of call center agents as Team B, what fraction of the total calls was processed by Team B?

A. 3/2
B. 3/4
C. 2/3
D. 1/2
E. 1/5


Say each member of Team B processes 5 calls and Team B has 8 agents, then the total number of calls processed by team B is 5*8=40;

Since each member of Team A was able to process 4/5 calls as compared to each member of Team B and Team A has 5/8 as many number of call center agents as Team B, then each member of Team A processes 4/5*5=4 calls and Team A has 5/8*8=5 agents. Thus, the total number of calls processed by Team A is 4*5=20;

Total calls processed by Team A and B is 40+20=60. Therefore, Team B processed 40/60=2/3 of the total calls.

Answer: C.

Hope it's clear.
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Re: A call center has two teams. Each member of Team A was able [#permalink] New post   31 Oct 2012, 05:48
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This problem is a bit misleading because you could think to solve for number of agents and then for calls ..............and in the meantime spin your head

Instead we have simply: Calls \(\frac{A}{B}\)\(\frac{4}{5}\) and \(\frac{A}{B}\) \(\frac{5}{8}\) agents

So A calls \(5*4= 20\)

B calls \(5*8=40\)

Tot \(A + B = 60\) ------> we want B : \(\frac{40}{60}\) \(=\) \(\frac{2}{3}\)

C is the answer
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Re: A call center has two teams. Each member of Team A was able [#permalink] New post   31 Oct 2012, 12:11
carcass wrote:
what is the source of this question ??

is not a proprer gmat like question because gmat use the brackets [ ] only if a number could be rounded to the next number i.e. : if [x] is 1.5 and x is rounded to the lower less than X what is X : 1 is X, i remember 1 or max 2 problems of this genere in the entire OG )

;)

this question is hired from GoGMAT
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Re: A call center has two teams. Each member of Team A was able [#permalink] New post   03 Mar 2014, 00:42
Let team B has 8 agents, so team A has 5 agents
Let each agent of team B picked up 5 calls, so total calls by team B = 40
So, each agent in Team A picked up 4 calls, so total calls for team A = 20

Fraction for team B = 40/(40+20) = 2/3 = Answer = C
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Re: A call center has two teams. Each member of Team A was able [#permalink] New post   25 Jan 2021, 02:25
No.of calls:
B= x; A=4/5x
No.of agents:
B=y; A=5/8y
Total calls made:
A= 4/5x*5/8y==> xy/2
B= xy

Now the ratio: A/B= xy/2 /xy==> 1/2

B's share= 2/3
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Re: A call center has two teams. Each member of Team A was able [#permalink]
25 Jan 2021, 02:25
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