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A math question from GMATPrep

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Manager
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A math question from GMATPrep [#permalink] New post 19 Apr 2007, 18:32
Hi,
If you know how to solve this problem, please explain it to me. Thanks!

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100
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Re: A math question from GMATPrep [#permalink] New post 19 Apr 2007, 19:07
GMAT_700 wrote:
Hi,
If you know how to solve this problem, please explain it to me. Thanks!

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100



200 6ounce = 100 12 ounces

Concentrate water juice
1 3 4
x y 100

100/4 = 25

Nos of concentrate cans required is 25
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 [#permalink] New post 19 Apr 2007, 19:12
1 can of concentrate -> mixed with 3 cans of water
For each mixture, we have 48 ounces of juice.

So if we need 200 6-ounce servings, total = 1200 ounces of juice.

# of cans = 1200/48 = 25 cans.
Manager
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 [#permalink] New post 19 Apr 2007, 19:36
Thanks for your answers, but I still do not understand how did you get 25.
  [#permalink] 19 Apr 2007, 19:36
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A math question from GMATPrep

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