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# A math question from GMATPrep

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Manager
Joined: 13 Mar 2007
Posts: 98
Followers: 1

Kudos [?]: 11 [0], given: 0

A math question from GMATPrep [#permalink]  19 Apr 2007, 18:32
Hi,
If you know how to solve this problem, please explain it to me. Thanks!

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100
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VP
Joined: 03 Apr 2007
Posts: 1376
Followers: 3

Kudos [?]: 260 [0], given: 10

Re: A math question from GMATPrep [#permalink]  19 Apr 2007, 19:07
GMAT_700 wrote:
Hi,
If you know how to solve this problem, please explain it to me. Thanks!

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

200 6ounce = 100 12 ounces

Concentrate water juice
1 3 4
x y 100

100/4 = 25

Nos of concentrate cans required is 25
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
Followers: 22

Kudos [?]: 184 [0], given: 0

1 can of concentrate -> mixed with 3 cans of water
For each mixture, we have 48 ounces of juice.

So if we need 200 6-ounce servings, total = 1200 ounces of juice.

# of cans = 1200/48 = 25 cans.
Manager
Joined: 13 Mar 2007
Posts: 98
Followers: 1

Kudos [?]: 11 [0], given: 0

Thanks for your answers, but I still do not understand how did you get 25.
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