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VeritasKarishma how would you use weighted average approach for this one?

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TomB
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make an orange juice. How many 12 ounce cans of concentrate are required to prepare 200 6-ounce servings of orange juice.

A. 25
B. 34
C. 50
D. 67
E. 100

vita60
You don't need to use weighted averages here since 2 simple ingredients are mixed to give one mixture only. You use weighted averages when 2 mixtures are mixed to give a third mixture. Use ratios to solve this:

On the ratio scale,
Concentrate : Water : Juice = 1: 3 : 4
(1 part concentrate mixed with 3 parts water to give 4 parts juice)

We need total 200*6 = 1200 ounces of juice. So the multiplier is 300.

300 ounces of concentrate will be mixed with 900 ounces of water to give 1200 ounces of juice.

Since we have 12 ounce cans, we will need 300/12 = 25 cans.

Answer (A)

Check: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/0 ... of-ratios/
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TomB
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make an orange juice. How many 12 ounce cans of concentrate are required to prepare 200 6-ounce servings of orange juice.

A. 25
B. 34
C. 50
D. 67
E. 100

Here's another approach:

The first part tells that, for every 1 can of concentrate, we can make 4 cans of juice.
Let's be even more generic, for 1 volume of concentrate, we can make 4 volumes of juice.

Okay, now notice that we have a problem with the volume mismatch in the question. It involves 12-ounce cans of concentrate and 6-ounce servings.
So, let's reword the question. Instead of making 200 6-ounce servings of juice, let's make 100 12-ounce servings of juice. We're still making the SAME AMOUNT OF JUICE.

We're now asking, "How many 12-ounce cans of the concentrate are required to prepare 100 12-ounce serving of orange juice?

We can solve this question using equivalent ratios.

We're comparing (volume of concentrate)/(volume of juice)

We get: 1/4 = x/100

Solve for x to get x=25

So, the answer is A

Cheers,
Brent

HI BrentGMATPrepNow, not quite sure about 200 6-ounce servings of juice = 100 12-ounce servings of juice ? and why is not 100 3 -ounce servings of juice if we are halfving it here? Thanks Brent
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Kimberly77
BrentGMATPrepNow
TomB
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make an orange juice. How many 12 ounce cans of concentrate are required to prepare 200 6-ounce servings of orange juice.

A. 25
B. 34
C. 50
D. 67
E. 100

Here's another approach:

The first part tells that, for every 1 can of concentrate, we can make 4 cans of juice.
Let's be even more generic, for 1 volume of concentrate, we can make 4 volumes of juice.

Okay, now notice that we have a problem with the volume mismatch in the question. It involves 12-ounce cans of concentrate and 6-ounce servings.
So, let's reword the question. Instead of making 200 6-ounce servings of juice, let's make 100 12-ounce servings of juice. We're still making the SAME AMOUNT OF JUICE.

We're now asking, "How many 12-ounce cans of the concentrate are required to prepare 100 12-ounce serving of orange juice?

We can solve this question using equivalent ratios.

We're comparing (volume of concentrate)/(volume of juice)

We get: 1/4 = x/100

Solve for x to get x=25

So, the answer is A

Cheers,
Brent

HI BrentGMATPrepNow, not quite sure about 200 6-ounce servings of juice = 100 12-ounce servings of juice ? and why is not 100 3 -ounce servings of juice if we are halfving it here? Thanks Brent

We have a volume mismatch in the question. It involves 12-ounce cans of concentrate and 6-ounce servings.
So, in my solution, I decided to convert 200 6-ounce servings of juice to 100 12-ounce servings of juice.
Notice that, if I combine two 6-ounce servings, I get one 12-ounce serving.

Does that help?
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Hello there! I am a bit confused on when to flip the ratio...
1can of concentrate and 3 cans of water --> c:w = 1:3
Here we do not flip the ratio but normally we do flip the ratio. Can someone help me understand? I think I am mixing concepts
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ruis
Hello there! I am a bit confused on when to flip the ratio...
1can of concentrate and 3 cans of water --> c:w = 1:3
Here we do not flip the ratio but normally we do flip the ratio. Can someone help me understand? I think I am mixing concepts
Here, it is a straight forward ratio, of exactly the same things what have been mentioned => concentrate : water

But say we have speed given in ratio 1:3, so time taken will be in the ratio 3:1.
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chetan2u

ruis
Hello there! I am a bit confused on when to flip the ratio...
1can of concentrate and 3 cans of water --> c:w = 1:3
Here we do not flip the ratio but normally we do flip the ratio. Can someone help me understand? I think I am mixing concepts
Here, it is a straight forward ratio, of exactly the same things what have been mentioned => concentrate : water

But say we have speed given in ratio 1:3, so time taken will be in the ratio 3:1.
­Thanks chetan :)
I mixed concenpts as in the following examples we flip the ratio
-- 3 variables involved: https://gmatclub.com/forum/at-a-certain ... ml#p641813
(I thought straight away it was 2:3... I understand the reasoning but I am not quick nor good with reasoning ratios... )
-- using weighted average https://gmatclub.com/forum/solution-x-which-is-50-alcohol-is-combined-with-solution-y-which-263106.html#p2776372
I have gone through all the content and I am practicing a lot to be able to get more confortable. Somehow I extrapolate one case to the rest... I have to take more time to think and try not to rush...
 
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