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# A portion of \$6600 is invested at a 5% annual return, while

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Senior Manager
Joined: 30 Aug 2003
Posts: 325
Location: dallas , tx
Followers: 1

Kudos [?]: 8 [0], given: 0

A portion of \$6600 is invested at a 5% annual return, while [#permalink]  15 Dec 2003, 11:27
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
A portion of \$6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year?
(A) \$180
(B) \$270
(C) \$300
(D) \$320
(E) \$360

any shortcuts??
_________________

shubhangi

Manager
Joined: 26 Aug 2003
Posts: 233
Location: United States
Followers: 1

Kudos [?]: 2 [0], given: 0

x = portion invested at 5%

0.05x = 2(0.03(6600 - x))
0.05x = 396 - 0.06x
x = 3600

Return on portion invested at 5% = 0.05(3600) = 180, so the rest of the portion should return 90.

Total return income = 180 + 90 = 270

You can do trial and error methold to get the values too but that may take longer... well depends. To me this theoretical approach was faster. Less than a minute.
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