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A square garden is surrounded by a 2 feet wide walkway on

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Vamshi8411
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A square garden is surrounded by a 2 feet wide walkway on [#permalink] New post   26 Jul 2012, 05:34
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A square garden is surrounded by a 2 feet wide walkway on each side.The area of the garden and the walkway is 225 square feet.If the garden is broadened by increasing side of the garden by 5 units then what will be the area of the garden?

A. 121
B. 169
C. 225
D. 256
E. 324
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D
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cyberjadugar
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Re: A square garden is surrounded by a 2 feet wide walkway [#permalink] New post   26 Jul 2012, 07:50
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Hi,

Area of garden & path = 225
Side = \(\sqrt{225}\) = 15 ft

As per the below diagram,
Attachment:
square.jpg
square.jpg [ 11.57 KiB | Viewed 15272 times ]

Side of garden = 11 ft

When sides of garden are increased by 5 ft,
new dimension = 11+5 = 16 ft
Area = \(16^2\) = 256

Answer (D)

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Re: A square garden is surrounded by a 2 feet wide walkway [#permalink] New post   26 Jul 2012, 09:49
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Thanks.

I missed to take 2 feet on both sides. so took the side of the garden as 15-2 =13.

so 13 +5 after increasing and the area of garden as 18^2 = 324.

Have to be careful :roll: . Thanks for the solution.
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Re: A square garden is surrounded by a 2 feet wide walkway on [#permalink] New post   27 May 2017, 04:17
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Let 'x' be the side of garden excluding the walkway.
Thus side of garden including the walkway = (x+4) (since its 2 feet on both sides)

Area = (x+4)^2 = 225 Or (x+4) = 15 Or x = 11

Right now side of square garden is 11 feet. New side = 11+5 = 16 feet
New Area = 16*16 = 256 sq feet

Hence D answer
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A square garden is surrounded by a 2 feet wide walkway on [#permalink] New post   28 Oct 2018, 15:09
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Solution



Given:
    • A square garden is surrounded by a 2 feet wide walkway on each side.
    • The area of the garden and the walkway is 225 square feet.
    • Garden is broadened by increasing side of the garden by 5 units.

To find:
    • Area of the garden if the garden is broadened by increasing side of the garden by 5 units.

Approach and Working

    • Let the side of the garden is x feet.
      o Hence, the side of garden +walkway= l+4 feet
      • \((x+4)^2\)= 225
        o x= 11
      • x+5= 16
      • \((x+5)^2\)= 256 feet.

Correct answer: Option D
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Re: A square garden is surrounded by a 2 feet wide walkway on [#permalink] New post   02 Jan 2021, 14:57
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Vamshi8411 wrote:
A square garden is surrounded by a 2 feet wide walkway on each side.The area of the garden and the walkway is 225 square feet.If the garden is broadened by increasing side of the garden by 5 units then what will be the area of the garden?

A. 121
B. 169
C. 225
D. 256
E. 324

Solution:

A side of the garden, including the walkway, currently is √225 = 15 ft. Without the walkway bordering the garden, the length of a side of the garden is 15 - 2 - 2 = 11 ft. Thus, when the side of the garden is increased by 5 ft, the area of the garden would be (11 + 5)^2 = 16^2 = 256 sq. ft.

Answer: D
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Re: A square garden is surrounded by a 2 feet wide walkway on [#permalink] New post   25 Aug 2023, 06:07
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Re: A square garden is surrounded by a 2 feet wide walkway on [#permalink]
25 Aug 2023, 06:07
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