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Re: are x , y > 0 ? 1) 2x-2y =1 2) x/y > 1 should we [#permalink]
some people get it and some people dont but i feel that if you have two variablee inequality DS problem, plotting the conditions on xy plane is the best method.. only thing is, dont try this in exam without practise

question : x,y > 0 ... target area is Q1

statement 1 : line passes through Q1, Q2 and Q3 ... not suff
statement 2 : green area ... in Q1 and Q3 .. not suff

combine, line segament in blue, alwasy in Q1 ...suff ..answer
Attachment:
DSQ3.JPG
DSQ3.JPG [ 9.55 KiB | Viewed 1644 times ]
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Re: are x , y > 0 ? 1) 2x-2y =1 2) x/y > 1 should we [#permalink]
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Let take one more example :
On number line , the distance between x and y is greater than distance between x and z. does z lie between x and y ?

1) xyz <0
2) xy<0

Now this resolves to is |X-Y| > |X-Z| ?

lets try solve algebracally and by sample data ... and see how much time each takes ...
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Re: are x , y > 0 ? 1) 2x-2y =1 2) x/y > 1 should we [#permalink]
abhaypratapsingh wrote:
Let take one more example :
On number line , the distance between x and y is greater than distance between x and z. does z lie between x and y ?

1) xyz <0
2) xy<0

Now this resolves to is |X-Y| > |X-Z| ?

lets try solve algebracally and by sample data ... and see how much time each takes ...


is it E

statement 1 ... clearly not suff ... x,y,z all can be -ve and you never know z was on which side of x
statement 2 ... not suff ... doesn tell anything about Z

combine : ...z is Positive
and one of x or y is negative ....

if y is negative .... both x and z are positive and z can be on either side of x ... not suff
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Re: are x , y > 0 ? 1) 2x-2y =1 2) x/y > 1 should we [#permalink]
durgesh79 wrote:
some people get it and some people dont but i feel that if you have two variablee inequality DS problem, plotting the conditions on xy plane is the best method.. only thing is, dont try this in exam without practise

question : x,y > 0 ... target area is Q1

statement 1 : line passes through Q1, Q2 and Q3 ... not suff
statement 2 : green area ... in Q1 and Q3 .. not suff

combine, line segament in blue, alwasy in Q1 ...suff ..answer
Attachment:
DSQ3.JPG


Isn't the green area colored incorrectly? If x/y > 1, that means that x>y. The graph should than be colored such that everything to the right of the line y=x is green. Am I missing something?
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Re: are x , y > 0 ? 1) 2x-2y =1 2) x/y > 1 should we [#permalink]
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mrblack wrote:
Isn't the green area colored incorrectly? If x/y > 1, that means that x>y. The graph should than be colored such that everything to the right of the line y=x is green. Am I missing something?


If x/y > 1, that means that:

x > y if y > 0
x < y if y < 0

Remember, we need to reverse the inequality if we multiply both sides by a negative number, and y can certainly be negative.
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Re: are x , y > 0 ? 1) 2x-2y =1 2) x/y > 1 should we [#permalink]
IanStewart wrote:
mrblack wrote:
Isn't the green area colored incorrectly? If x/y > 1, that means that x>y. The graph should than be colored such that everything to the right of the line y=x is green. Am I missing something?


If x/y > 1, that means that:

x > y if y > 0
x < y if y < 0

Remember, we need to reverse the inequality if we multiply both sides by a negative number, and y can certainly be negative.


Thanks. That's a very good point. I got it now.



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