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Assistance needed, GMAT prep

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Joined: 07 Aug 2009
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Assistance needed, GMAT prep [#permalink] New post 14 Sep 2009, 09:55
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...attached are 4 questions from the GMAT prep, i got really beaten up by. Any assistance to would be very much appreciated
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Re: Assistance needed, GMAT prep [#permalink] New post 14 Sep 2009, 10:47
PGY001 wrote:
...attached are 4 questions from the GMAT prep, i got really beaten up by. Any assistance to would be very much appreciated

I will respond to the first two. I have seen the other two on this forums, so please do a search.

#7:

Given:
bdc = 2x.
Therefore, bda=180-2x
Therefore, abd = 180 - adb - bad = 180 - (180-2x) - x = x.
Therefore, ad = bd.
Now, bd = bc (since bdc = bcd = 2x.
Therefore, bc = ad.

St.1: ad = 6.
Therefore, bc = 6. SUFF.

St. 2: x = 36.
No info any of the lengths. Insuff.

A.
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Re: Assistance needed, GMAT prep [#permalink] New post 14 Sep 2009, 10:51
#12:

Let x = the height of the triangle.

Therefore, x^2 = t^2 - (t/2)^2 (Pythagoras theorem.)
Therefore, x = t* 3^(1/2) / 2

Therefore, area = 1/2 * t * t* 3^(1/2) / 2 = t^2 * 3^(1/2) / 4.

Area of square = s^2.

Therefore, t^2 * 3^(1/2) / 4 = s^2

Solving, t:s = 2: 3^(1/4)
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Joined: 07 Aug 2009
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Re: Assistance needed, GMAT prep [#permalink] New post 15 Sep 2009, 13:01
cheers Gmat Tiger...i do appreciate this a lot
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Joined: 07 Aug 2009
Posts: 5
Location: Accra, Ghana
Schools: Wharton, HBS, Kellog
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Kudos [?]: 0 [0], given: 0

Re: Assistance needed, GMAT prep [#permalink] New post 15 Sep 2009, 13:04
cheers Gmat Tiger...very much appreciated
Re: Assistance needed, GMAT prep   [#permalink] 15 Sep 2009, 13:04
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