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Re: decimals squared, cubed etc. & compound interest [#permalink]
Wow that's awesome -thanks! Definitely will be a time saver on compound interest problems!
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Re: decimals squared, cubed etc. & compound interest [#permalink]
No problem! Glad you were able to understand my ramblings.
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Re: decimals squared, cubed etc. & compound interest [#permalink]
Wow, really useful, thanks for the tip! :)
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Re: decimals squared, cubed etc. & compound interest [#permalink]
Could you help me solve 1.50^2?
= 1.(50*2) 50^2
=1.35
:(

Can u tell me where I am going wrong here.
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Re: decimals squared, cubed etc. & compound interest [#permalink]
vancypants wrote:
sanram2205 wrote:
Could you help me solve 1.50^2?
= 1.(50*2) 50^2
=1.35
:(

Can u tell me where I am going wrong here.


Super late, but I hope this helps someone.

Like you mention the first part you have is good [= 1.(50*2) 50^2], but you just need a little extra decimal movement to get the right answer.

If we multiply that part out, you'll get 1.(100)(2500). As YourDreamTheater mentioned above, when you have a three-digit number as the answer to the (x*2) or the (x^2) part, you need to move the whole number one decimal place LEFT before you add it. The same goes for a number with 4 digits (e.g., 2500), but it will have to move TWO digits to the left before you add it.

Thus, the answer to 1.5^2 will look more like this:

= 1.(50*2)(50^2)
= 1.(100)(2500)
= (added vertically showing how the numbers moved to the left)
1.00
1.00 (.100 moved left ONE decimal)
0.2500 (.002500 moved left TWO decimals)
---------
= 2.2500 = 2.25 = 1.5^2




Hi, It helps me. But could you please show how it works for 5.5
It does not give me correct result :(
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Re: decimals squared, cubed etc. & compound interest [#permalink]

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