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# GMAT PREP (PS)

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Director
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GMAT PREP (PS) [#permalink]  06 May 2010, 11:34
00:00

Difficulty:

(N/A)

Question Stats:

25% (02:45) correct 75% (00:33) wrong based on 7 sessions
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PS4.PNG [ 20.63 KiB | Viewed 2111 times ]

Math Expert
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Re: GMAT PREP (PS) [#permalink]  06 May 2010, 12:05
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LM wrote:
In the figures above, if the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S=

Property of similar triangles: In two similar triangles, the ratio of their areas is the square of the ratio of their sides.

Hence $$\frac{AREA}{area}=\frac{S^2}{s^2}=2$$ --> $$S=s\sqrt{2}$$.

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Re: GMAT PREP (PS) [#permalink]  06 May 2010, 12:34
Bunuel wrote:
LM wrote:

Property of similar triangles: In two similar triangles, the ratio of their areas is the square of the ratio of their sides.

Hence $$\frac{AREA}{area}=\frac{S^2}{s^2}=2$$ --> $$S=s\sqrt{2}$$.

Thanks I did not know this! the ratio of their areas is the square of the ratio of their sides.
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Re: GMAT PREP (PS) [#permalink]  25 Aug 2010, 01:24
Bunuel that was awesome...although read all concepts in your Polygon blog..but did not click to me. +1 to you as always
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Re: GMAT PREP (PS) [#permalink]  08 Sep 2010, 05:39
This is certainly not a 700 Level question Bunuel can be moved
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I eliminated A and B for this because I knew that S had to be greater than s, but I did not know how to find the exact answer. I also eliminated 2s because that excludes the height when calculating area, but again I could not figure out how to get the exact answer. Any help please?? Thanks!!! The file is attached.

Jeremiah
Attachments

Geo PS1.docx [57.39 KiB]

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Merging similar topics.
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Re: GMAT PREP (PS) [#permalink]  23 Oct 2010, 09:08
If you don't know the property:
take H=height of the larger triangle
and h=height of the smaller triangle

As the area is twice ,so HS=2hs
because triangles are similar h/s=H/S or h/H=s/S

Now after solving we get S=(2^1/2)s
Re: GMAT PREP (PS)   [#permalink] 23 Oct 2010, 09:08
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