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Manager
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Joined: 01 Mar 2009
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Help pls [#permalink] New post 02 Mar 2009, 14:29
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi would appreciate any help with this question.

Thanks!

__________________________________________________________________________________________________________

1.
PSQ form a right triangle with S as the Right angle, P as the bottom angle and Q as the top angle.
PSR form a right triangle inside PSQ. The measure of angle PRS is how many degrees greater than the measure of angle PQR.
No other information is given.

1)The measure of angle QPR is 30
2)The sum of PQR and PRQ is 150.

Answer: D (each statement alone is efficient)
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Senior Manager
Senior Manager
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Joined: 24 Feb 2007
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Location: nj
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Re: Help pls [#permalink] New post 05 Mar 2009, 12:40
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suppose

PRQ = x
PQR = y
QPR = z
PRS = a

then

we know a = y + z and we've to find out a-y

from 1) z = 30
so a-y = 30 --> suff

from 2) x+y = 30

a+x = 180
a+ 30 - y = 180
a-y = 30 ---> suff
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Manager
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Schools: Booth (Admit R1), Sloan (Ding R1), Tuck (R1)
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Re: Help pls [#permalink] New post 05 Mar 2009, 16:16
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zalan wrote:
Hi would appreciate any help with this question.

Thanks!

__________________________________________________________________________________________________________

1.
PSQ form a right triangle with S as the Right angle, P as the bottom angle and Q as the top angle.
PSR form a right triangle inside PSQ. The measure of angle PRS is how many degrees greater than the measure of angle PQR.
No other information is given.

1)The measure of angle QPR is 30
2)The sum of PQR and PRQ is 150.

Answer: D (each statement alone is efficient)


D can be worked out in one of the interpretation of the question. In another interpretation it could be tricky. See attached illustration for explanation. Thanks.
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Manager
Manager
avatar
Joined: 01 Mar 2009
Posts: 52
Followers: 1

Kudos [?]: 3 [0], given: 2

Re: Help pls [#permalink] New post 05 Mar 2009, 20:05
Thank you both for taking the time. I keep forgetting the rule where the two opposite angles from the adjacent angle of target equals the target angle.

*cheers!*
Re: Help pls   [#permalink] 05 Mar 2009, 20:05
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