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# Help pls

Author Message
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Manager
Joined: 01 Mar 2009
Posts: 52
Followers: 1

Kudos [?]: 1 [0], given: 2

Help pls [#permalink]  02 Mar 2009, 14:29
Hi would appreciate any help with this question.

Thanks!

__________________________________________________________________________________________________________

1.
PSQ form a right triangle with S as the Right angle, P as the bottom angle and Q as the top angle.
PSR form a right triangle inside PSQ. The measure of angle PRS is how many degrees greater than the measure of angle PQR.
No other information is given.

1)The measure of angle QPR is 30
2)The sum of PQR and PRQ is 150.

Answer: D (each statement alone is efficient)
Senior Manager
Joined: 24 Feb 2007
Posts: 267
Location: nj
Followers: 1

Kudos [?]: 75 [1] , given: 2

Re: Help pls [#permalink]  05 Mar 2009, 12:40
1
KUDOS
suppose

PRQ = x
PQR = y
QPR = z
PRS = a

then

we know a = y + z and we've to find out a-y

from 1) z = 30
so a-y = 30 --> suff

from 2) x+y = 30

a+x = 180
a+ 30 - y = 180
a-y = 30 ---> suff
Manager
Joined: 26 Dec 2008
Posts: 58
Schools: Booth (Admit R1), Sloan (Ding R1), Tuck (R1)
Followers: 2

Kudos [?]: 11 [1] , given: 0

Re: Help pls [#permalink]  05 Mar 2009, 16:16
1
KUDOS
zalan wrote:
Hi would appreciate any help with this question.

Thanks!

__________________________________________________________________________________________________________

1.
PSQ form a right triangle with S as the Right angle, P as the bottom angle and Q as the top angle.
PSR form a right triangle inside PSQ. The measure of angle PRS is how many degrees greater than the measure of angle PQR.
No other information is given.

1)The measure of angle QPR is 30
2)The sum of PQR and PRQ is 150.

Answer: D (each statement alone is efficient)

D can be worked out in one of the interpretation of the question. In another interpretation it could be tricky. See attached illustration for explanation. Thanks.
Attachments

triangle solution.doc [29 KiB]

Manager
Joined: 01 Mar 2009
Posts: 52
Followers: 1

Kudos [?]: 1 [0], given: 2

Re: Help pls [#permalink]  05 Mar 2009, 20:05
Thank you both for taking the time. I keep forgetting the rule where the two opposite angles from the adjacent angle of target equals the target angle.

*cheers!*
Re: Help pls   [#permalink] 05 Mar 2009, 20:05
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