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I've attached my picture; my notes are in blue. Hopefully it

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jcgoodchild
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I've attached my picture; my notes are in blue. Hopefully it [#permalink] New post   Updated on: 15 Apr 2006, 15:27
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A
B
C
D
E

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(N/A)

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I've attached my picture; my notes are in blue. Hopefully it makes sense.



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Originally posted by jcgoodchild on 15 Apr 2006, 15:25.
Last edited by jcgoodchild on 15 Apr 2006, 15:27, edited 1 time in total.
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jcgoodchild
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Re: I've attached my picture; my notes are in blue. Hopefully it [#permalink] New post   15 Apr 2006, 15:27
Sorry, I meant the answer is A in my picture. We only need to know that length. I'll edit, and repost it.
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SunShine
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Re: I've attached my picture; my notes are in blue. Hopefully it [#permalink] New post   15 Apr 2006, 15:38
A.

Your explanation is quite right, but the answe should be A.

AD=BD (ISOSCLE) = 6

BD = BC = 6, (isoscale)

jcgoodchild wrote:
I've attached my picture; my notes are in blue. Hopefully it makes sense.
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jlui4477
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Re: I've attached my picture; my notes are in blue. Hopefully it [#permalink] New post   15 Apr 2006, 16:23
how did you know that the left angle is x degree?

I understood the 180-2x and 180-4x.
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Re: I've attached my picture; my notes are in blue. Hopefully it [#permalink] New post   15 Apr 2006, 16:32
Another easy way out:

Angle BDC is an Exterior angle of the triangle BAD. And in any traingle exterior angle is equal to the sum of the interior opposite angles. Hence

BDC = BAD + ABD
2x = x + ABD
=> ABD = x
Hence triangle BAD is isoceles
=> AD = BD = 6



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!
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Re: I've attached my picture; my notes are in blue. Hopefully it [#permalink]
15 Apr 2006, 16:32
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