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If n is not negative, is n integer?

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Bunuel
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If n is not negative, is n integer? [#permalink] New post   25 Dec 2016, 02:29
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A
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E

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67% (01:12) correct 33% (01:20) wrong based on 47 sessions
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If n is not negative, is n integer?

(1) n^2 < 1
(2) n^4 < 1
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E
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vitaliyGMAT
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Re: If n is not negative, is n integer? [#permalink] New post   25 Dec 2016, 04:40
Bunuel wrote:
If n is not negative, is n integer?

(1) n^2 < 1
(2) n^4 < 1


(1) n^2 < 1

This can give us n=0 integer and n=1/x not an integer. Insufficient.

(2) n^4 < 1 Same as in previous case. The only difference is that \(\frac{1}{x^4}\) will be closer to 0. Insufficien.

(1) & (2) By combining above two we still can get n as 0 or fraction < 1. Insufficient.

Answer E
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hershkoch
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Re: If n is not negative, is n integer? [#permalink] New post   26 Dec 2016, 02:26
vitaliyGMAT wrote:
Bunuel wrote:
If n is not negative, is n integer?

(1) n^2 < 1
(2) n^4 < 1


(1) n^2 < 1

This can give us n=0 integer and n=1/x not an integer. Insufficient.

(2) n^4 < 1 Same as in previous case. The only difference is that \(\frac{1}{x^4}\) will be closer to 0. Insufficien.

(1) & (2) By combining above two we still can get n as 0 or fraction < 1. Insufficient.

Answer E



Hi, Shouldn't it be C, as zero is common between one and two.. thanks
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Mo2men
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Re: If n is not negative, is n integer? [#permalink] New post   26 Dec 2016, 02:38
hershkoch wrote:
vitaliyGMAT wrote:
Bunuel wrote:
If n is not negative, is n integer?

(1) n^2 < 1
(2) n^4 < 1


(1) n^2 < 1

This can give us n=0 integer and n=1/x not an integer. Insufficient.

(2) n^4 < 1 Same as in previous case. The only difference is that \(\frac{1}{x^4}\) will be closer to 0. Insufficien.

(1) & (2) By combining above two we still can get n as 0 or fraction < 1. Insufficient.

Answer E



Hi, Shouldn't it be C, as zero is common between one and two.. thanks


Take n=1/2. It satisfies both statements too.

Answer: E
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Re: If n is not negative, is n integer? [#permalink]
26 Dec 2016, 02:38
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Bunuel
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