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# if p and q are positive integers, what is the value of q? 1)

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if p and q are positive integers, what is the value of q? 1) [#permalink]

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03 Oct 2008, 11:27
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if p and q are positive integers, what is the value of q?

1) q^p-1 =1
2) p=1

the answer is E, but why is not C?

both together, you've got q^1-1 =1 => q^0=1 => q=1
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03 Oct 2008, 11:31
andreasonlinegr wrote:
if p and q are positive integers, what is the value of q?

1) q^p-1 =1
2) p=1

the answer is E, but why is not C?

both together, you've got q^1-1 =1 => q^0=1 => q=1

Q^0 is not defined. !
it should be E!!
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03 Oct 2008, 12:39
I also get (C)

q^1 = 2

q = 2

Maybe you forgot () as in q^(p-1) ?

Then the answer is indeed (E)

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03 Oct 2008, 13:38
andreasonlinegr wrote:
if p and q are positive integers, what is the value of q?

1) q^p-1 =1
2) p=1

the answer is E, but why is not C?

both together, you've got q^1-1 =1 => q^0=1 => q=1

What is statement 1? Is it $$q^(p-1)$$ = 1" or "($$q^p$$) - 1 = 1"?
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03 Oct 2008, 13:43
elmagnifico wrote:
andreasonlinegr wrote:
if p and q are positive integers, what is the value of q?

1) q^p-1 =1
2) p=1

the answer is E, but why is not C?

both together, you've got q^1-1 =1 => q^0=1 => q=1

Q^0 is not defined. !
it should be E!!

Q^0 is defined. Anything has 0 power is always 1.
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03 Oct 2008, 15:11
it's q^p-1=1 without parenthesis ()

You are right q is not defined, q could be 0, it could be 1, -1...
Re: power   [#permalink] 03 Oct 2008, 15:11
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