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If P = n(n-1)(n-2)...(1) amd n>2, what is the largest

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If P = n(n-1)(n-2)...(1) amd n>2, what is the largest [#permalink] New post 11 Sep 2004, 22:06
If P = n(n-1)(n-2)...(1) amd n>2, what is the largest value of integer n where P has zero as its last 6 digits and a non-zero digit for its millions place
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Re: if p =n(n-1)n-2) [#permalink] New post 11 Sep 2004, 23:01
Anonymous wrote:
If P = n(n-1)(n-2)...(1) amd n>2, what is the largest value of integer n where P has zero as its last 6 digits and a non-zero digit for its millions place


29

Did it by enumeration ... not sure if this is the best way to solve this kinda problem.

1...10 2 zeros .... 2*5 and 10
11..20 2 zeros ..... same logic
21..25 2 zeros ..... 25 is 5 times 5 ... hence 1 zero comes from 22*5 and the other zero comes from 24*5

Hence we get the 6 zeros needed and highest value of n is 29
Re: if p =n(n-1)n-2)   [#permalink] 11 Sep 2004, 23:01
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If P = n(n-1)(n-2)...(1) amd n>2, what is the largest

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