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# If the area of triangular region RST is 25, what is the

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If the area of triangular region RST is 25, what is the [#permalink]  21 May 2008, 01:53
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If the area of triangular region RST is 25, what is the perimeter of RST?

(1) The length of one side of RST is $$5\sqrt{2}$$.
(2) RST is a right isosceles triangle.
[Reveal] Spoiler: OA

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Last edited by Bunuel on 25 Oct 2013, 06:45, edited 1 time in total.
Edited the question and added the OA
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Re: DS2-24 [#permalink]  21 May 2008, 02:21
prasannar wrote:
24. If the area of triangular region RST is 25, what is the perimeter of RST?
(1) The length of one side of RST is 5 sqrt 2.
(2) RST is a right isosceles triangle.

Plz explain

B

1/2*a^2 = 25 --> a =?
then b =a*sqare root(2)

and perimeter = b+ 2a, suff
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Re: DS2-24 [#permalink]  21 May 2008, 02:30
(1) The length of one side is given . but no information abt other sides. Insufficient
(2)The triangle is right isosceles let one side be x So area=1/2 *base*height=25.
here base=height (isoscels triagle)=x
Therefore, 1/2 *x*x=25 so x can be found
since right triangle so third side can be found say y
Perimeter is 2x+y
So sufficient
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Re: DS2-24 [#permalink]  21 May 2008, 02:47
The question stem tells us that 1/2 * b * h = 25 and asks us to determine what RS + ST + TR is.

(1) Statement just tells us what one of the 3 sides is where the b and h could still take several values and affect the other two sides:

Insufficient

(2) This statement simply tells us that b = h so b^2 = 50. If we know the lengths of two sides of a right triangle, then we can determine (I won't calculate it here since it would be a waste of time on test day) the length of the other. So:

Sufficient

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Re: DS2-24 [#permalink]  21 May 2008, 05:47
I think C is right..how do we know from B which side is base?

i mean i could have a 90-degree-45-45 isso triangle and it will have perimeter of 10+5+5=20..

i could have a different isso triangle..
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Re: DS2-24 [#permalink]  21 May 2008, 13:05
i dont get it ... from B, you know that base=height=5*root(2) .... and since its a right isoceles, the hypotenuse will be 10 ... wont it ?
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Re: DS2-24 [#permalink]  21 May 2008, 13:46
pmenon wrote:
i dont get it ... from B, you know that base=height=5*root(2) .... and since its a right isoceles, the hypotenuse will be 10 ... wont it ?

no it wont..just draw a 3-4-5 right angle tirangle or a 5-12-13 right angle,triangle..
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Re: DS2-24 [#permalink]  21 May 2008, 14:28
but a 3-4-5 isnt an isoceles triangle ... or am i missing something ?
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Re: DS2-24 [#permalink]  21 May 2008, 14:39
fresinha12 wrote:
pmenon wrote:
i dont get it ... from B, you know that base=height=5*root(2) .... and since its a right isoceles, the hypotenuse will be 10 ... wont it ?

no it wont..just draw a 3-4-5 right angle tirangle or a 5-12-13 right angle,triangle..

Doesn't a right isosceles triangle means that the two equal sides make up the right angle?
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Re: DS2-24 [#permalink]  21 May 2008, 19:31
the answer should be B since in a right isosceles triangle, base = height and area is (base*height)/2 - so we can get both the sides and then hypotenuse is side*sqrt 2 - so I am a bit surprised that the answer is C - it is anyway not A and D. E is also out of the question.
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Re: DS2-24 [#permalink]  21 May 2008, 20:47
fresinha12 wrote:
I think C is right..how do we know from B which side is base?

i mean i could have a 90-degree-45-45 isso triangle and it will have perimeter of 10+5+5=20..

i could have a different isso triangle..

hi fresinha12,
is it required to know whats the base???
in any case let what ever be the base the area will be same
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Re: DS2-24 [#permalink]  25 Oct 2013, 05:40
rohit929 wrote:
fresinha12 wrote:
I think C is right..how do we know from B which side is base?

i mean i could have a 90-degree-45-45 isso triangle and it will have perimeter of 10+5+5=20..

i could have a different isso triangle..

hi fresinha12,
is it required to know whats the base???
in any case let what ever be the base the area will be same

I agree with Rohit, you can change the position but the relative sides will be the same hence you can trace a perpendicular for the height wherever you want and you would still have the same area and same perimeter.

Hence for me (B) is the correct choce
Let us know if this is the OA will you?
Thanks
Cheers
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Re: DS2-24 [#permalink]  25 Oct 2013, 06:51
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Expert's post
jlgdr wrote:
rohit929 wrote:
fresinha12 wrote:
If the area of triangular region RST is 25, what is the perimeter of RST?

(1) The length of one side of RST is $$5\sqrt{2}$$.
(2) RST is a right isosceles triangle.

I think C is right..how do we know from B which side is base?

i mean i could have a 90-degree-45-45 isso triangle and it will have perimeter of 10+5+5=20..

i could have a different isso triangle..

hi fresinha12,
is it required to know whats the base???
in any case let what ever be the base the area will be same

I agree with Rohit, you can change the position but the relative sides will be the same hence you can trace a perpendicular for the height wherever you want and you would still have the same area and same perimeter.

Hence for me (B) is the correct choce
Let us know if this is the OA will you?
Thanks
Cheers
J

The correct answer is B. From (2) we know that 1/2*leg^2=25 --> we can get the length of the legs, and since it's a 45-45-90 right isosceles triangle, we can get the length of the hypotenuse too.
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Re: If the area of triangular region RST is 25, what is the [#permalink]  07 Dec 2013, 10:57
I don't understand why (1) is not sufficient. Doesn't (1) imply that the triangle is an isosceles right triangle since the height = 5*sqrt(2)?
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Re: If the area of triangular region RST is 25, what is the [#permalink]  08 Dec 2013, 06:03
Expert's post
TooLong150 wrote:
I don't understand why (1) is not sufficient. Doesn't (1) imply that the triangle is an isosceles right triangle since the height = 5*sqrt(2)?

No. Any triangle with the base (side) of $$5\sqrt{2}$$ and height of $$\frac{10}{\sqrt{2}}$$ would have the area of 25.
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Re: If the area of triangular region RST is 25, what is the [#permalink]  09 Dec 2014, 14:42
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If the area of triangular region RST is 25, what is the [#permalink]  15 Feb 2015, 02:00
So the prompt tells us that the area of a triangle is 25 or that b*h=50
we are looking for the perimeter

(I) doesn't really tell us anything. Giving us one side is useless because we have no idea what the other sides could be
(II) actually tells us quite a lot. The fact that it is an isosceles right triangle tells us that b=h, so we know that those sides are rt(50) long and we can use that information to figure out the hypotenuse and add them up to get the perimeter.
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Re: If the area of triangular region RST is 25, what is the [#permalink]  19 Oct 2015, 10:55
B.
Statement 1- insufficient just says one side is 5 root 2 but no info about the other 2 sides is given
Statement 2- sufficient .. Isosceles right angled triangle therefore 1/2*side^2=25 side^2=50 side =root 50
Therefore hypotenuse = 2* (5 root 2) = 10
Perimeter =. 2(root 50) + 10
Re: If the area of triangular region RST is 25, what is the   [#permalink] 19 Oct 2015, 10:55
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