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# If the average (arithmetic mean) of x, y, and 20 is 10

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If the average (arithmetic mean) of x, y, and 20 is 10 [#permalink]  01 Dec 2005, 13:31
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If the average (arithmetic mean) of x, y, and 20 is 10 greater than the average of x, y, 20, and 30, what is the average of x and y?

A. 40
B. 45
C. 60
D. 75
E. 95
VP
Joined: 22 Aug 2005
Posts: 1123
Location: CA
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E. 95

(x+y+20)/3 = 10 + (x + y + 50)/4

solve for (x+y)

find out : (x+y)/2
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GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
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(x+y+20)/3 -10 = (x+y+20+30)/4
(x+y)/3 + 20/3 -10 = (x+y)/4 + 50/4
(x+y)/12 = 95/6
(x+y)/2 = 95
Senior Manager
Joined: 03 Nov 2005
Posts: 397
Location: Chicago, IL
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Kudos [?]: 28 [0], given: 17

(x+y+20)/3=a and (x+y+20+30)/4=a-10

3a=x+y+20 and 4a-40=x+y+20+30

a=70

(x+y+20)/3=70; x+y=95
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Senior Manager
Joined: 14 Apr 2005
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Re: one more PS [#permalink]  02 Dec 2005, 02:49
sem wrote:
If the average (arithmetic mean) of x, y, and 20 is 10 greater than the average of x, y, 20, and 30, what is the average of x and y?

A. 40
B. 45
C. 60
D. 75
E. 95

E - 95

(X+Y+20)/3 - (x+y+20+30)/4 = 10
Gives X+y = 190
or (X+Y)/2= 95
Re: one more PS   [#permalink] 02 Dec 2005, 02:49
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# If the average (arithmetic mean) of x, y, and 20 is 10

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