Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In a $10 game of chance in Las Vegas, there are two identica [#permalink]

Show Tags

28 Aug 2012, 18:10

In a $10 game of chance in Las Vegas, there are two identical bowls that contain 100 marbles. Each bowl contains black colored 95 marbles along with 5 different colored marbles: one blue, one yellow, one green, one red and one gold. You get to pick one marble randomly from each bowl. If you get a matching pair of colored marbles (blue-blue, gold-gold), you win $10000. What is the probability that you win the prize in one play of the game?

HEre's what I tried :

Method 1 = total pairs = 100; Total combinations = 100*100 => PRob = 1/100

Method 2 (really crash landed) --

Choose 1 of the black colored balls from the first bowl and then the second one => 95C1 * 95C1 Choose 1 of blue balls => 1C1 * 1C1 ...Now this will be done for all the five colors. Hence, total = 5*1c1 * 1c1 = 5

Your solution is incorrect because you forgot three-of-a-kind with a fourth different number.

For problems like this, with multiple "wins," far and away the easier solution is to find the odds of NOT getting what we want. In this case, we fail if and only if all four dice are different. So, we fail 6*5*4*3/6*6*6*6 of the time. Reducing, that gives us 5*4*3/6*6*6 --> 5*2*1/6*6 --> 5/18. And thus, we succeed 18/18 - 5/18 = 13/18 of the time. This is much easier, and much simpler, than doing all the counting of permutations! _________________

In a $10 game of chance in Las Vegas, there are two identical bowls that contain 100 marbles. Each bowl contains black colored 95 marbles along with 5 different colored marbles: one blue, one yellow, one green, one red and one gold. You get to pick one marble randomly from each bowl. If you get a matching pair of colored marbles (blue-blue, gold-gold), you win $10000. What is the probability that you win the prize in one play of the game?

HEre's what I tried :

Method 1 = total pairs = 100; Total combinations = 100*100 => PRob = 1/100

Method 2 (really crash landed) --

Choose 1 of the black colored balls from the first bowl and then the second one => 95C1 * 95C1 Choose 1 of blue balls => 1C1 * 1C1 ...Now this will be done for all the five colors. Hence, total = 5*1c1 * 1c1 = 5

Total = (95^2 + 5)/(100^2) = CRASHED !

Can any of the experts please help me ?

Thanks

Note here that 'matching pair of colored marbles' implies only the 5 non-black colors. I agree that there is some ambiguity here - is black considered a colored marble or not? Well, if you are to win $10,000 from a $10 game, a pair of black marbles should not help you win that kind of money so I assume that we are only talking about the 5 different colored marbles.

Probability of picking a non black marble from a bowl = 5/100 Probability of picking the same color marble from the other bowl = 1/100

Probability of a matching non black pair = (5/100)*(1/100) = 5/10000 = 1/2000

On a side note, notice that the probability is against the player. If the probability of winning is 1/2000, for one's $10, one should get $20,000 if one wins. That is why, the house always wins and one should not gamble! _________________

Re: If 4 fair dice are thrown simulatenously, what is the probab [#permalink]

Show Tags

29 Aug 2012, 07:22

KapTeacherEli wrote:

Hi Voodoo,

Your solution is incorrect because you forgot three-of-a-kind with a fourth different number.

For problems like this, with multiple "wins," far and away the easier solution is to find the odds of NOT getting what we want. In this case, we fail if and only if all four dice are different. So, we fail 6*5*4*3/6*6*6*6 of the time. Reducing, that gives us 5*4*3/6*6*6 --> 5*2*1/6*6 --> 5/18. And thus, we succeed 18/18 - 5/18 = 13/18 of the time. This is much easier, and much simpler, than doing all the counting of permutations!

Thanks Eli! You are correct. There are four possibilities:

Check out this awesome article about Anderson on Poets Quants, http://poetsandquants.com/2015/01/02/uclas-anderson-school-morphs-into-a-friendly-tech-hub/ . Anderson is a great place! Sorry for the lack of updates recently. I...

As you leave central, bustling Tokyo and head Southwest the scenery gradually changes from urban to farmland. You go through a tunnel and on the other side all semblance...

Ghibli studio’s Princess Mononoke was my first exposure to Japan. I saw it at a sleepover with a neighborhood friend after playing some video games and I was...