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In right polygon ABCDE, what is the angle ABE

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gmat_crack
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In right polygon ABCDE, what is the angle ABE [#permalink] New post   27 May 2006, 12:40
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In right polygon ABCDE, what is the angle ABE?



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Re: In right polygon ABCDE, what is the angle ABE [#permalink] New post   27 May 2006, 13:09
gmat_crack wrote:
In right polygon ABCDE, what is the angle ABE?


hey sanju, you mean right = regular?

=[180-{(3x180)/5}]/2 = 26
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Re: In right polygon ABCDE, what is the angle ABE [#permalink] New post   27 May 2006, 13:29
Professor wrote:
gmat_crack wrote:
In right polygon ABCDE, what is the angle ABE?


hey sanju, you mean right = regular?

=[180-{(3x180)/5}]/2 = 26


Hey Prof.,

This the question I have. Even I'm not sure what is the meaning of right.
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Re: In right polygon ABCDE, what is the angle ABE [#permalink] New post   28 May 2006, 10:26
hm..still not solved...

abcde is regular pentagon

each angle is (180)(5-2) / 5 = 108'

(180 - 108)/2 = 36'
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Re: In right polygon ABCDE, what is the angle ABE [#permalink] New post   28 May 2006, 10:28
assuming a regular pentagon , 5 equal sides , the answer should be 36 .

all the angles in regular polygon angle is 108 .
abe is an isosceles triangle .
so angle abe = (180 -108) / 2 = 36



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Re: In right polygon ABCDE, what is the angle ABE [#permalink]
28 May 2006, 10:28
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