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In the figure above, what is the area of triangular region B

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In the figure above, what is the area of triangular region B [#permalink] New post 03 Feb 2014, 00:13
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

93% (01:55) correct 8% (00:57) wrong based on 73 sessions
The Official Guide For GMAT® Quantitative Review, 2ND Edition

Attachment:
Untitled.png
Untitled.png [ 11.64 KiB | Viewed 1051 times ]
In the figure above, what is the area of triangular region BCD ?

(A) 4\sqrt{2}
(B) 8
(C) 8\sqrt{2}
(D) 16
(E) 16\sqrt{2}

Problem Solving
Question: 71
Category: Geometry Triangles; Area
Page: 71
Difficulty: 550


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Re: In the figure above, what is the area of triangular region B [#permalink] New post 03 Feb 2014, 00:13
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SOLUTION

Image
In the figure above, what is the area of triangular region BCD ?

(A) 4\sqrt{2}
(B) 8
(C) 8\sqrt{2}
(D) 16
(E) 16\sqrt{2}

Using Pythagorean theorem BD=\sqrt{4^2+4^2}=4\sqrt{2}.

The area of triangle BCD = \frac{1}{2}*BD*BC=\frac{1}{2}*4\sqrt{2}*4=8\sqrt{2}.

Answer: C.
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Re: In the figure above, what is the area of triangular region B [#permalink] New post 03 Feb 2014, 02:30
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In the figure above, what is the area of triangular region BCD ?

(A) 4\sqrt{2}
(B) 8
(C) 8\sqrt{2}
(D) 16
(E) 16\sqrt{2}



Sol: In the given question Triangle ABD is isosele with sides AB=AD=4 and therefore BD=4\sqrt{2}

Area of triangle BCD is 1/2*4*4\sqrt{2}

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Ans is C
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Re: In the figure above, what is the area of triangular region B [#permalink] New post 03 Feb 2014, 07:05
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its C.


BD will be 4square root 2. (that will be base) * 4/2=8 square root 2.
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Re: In the figure above, what is the area of triangular region B [#permalink] New post 03 Feb 2014, 10:16
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Ans C

First we calculate BD by Hypotenuse Theorem:
BD=\sqrt{4^2+4^2}=4\sqrt{2}

Area BCD=1/2 * 4\sqrt{2} * 4= 8\sqrt{2}
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Re: In the figure above, what is the area of triangular region B [#permalink] New post 08 Feb 2014, 01:47
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SOLUTION

Image
In the figure above, what is the area of triangular region BCD ?

(A) 4\sqrt{2}
(B) 8
(C) 8\sqrt{2}
(D) 16
(E) 16\sqrt{2}

Using Pythagorean theorem BD=\sqrt{4^2+4^2}=4\sqrt{2}.

The area of triangle BCD = \frac{1}{2}*BD*BC=\frac{1}{2}*4\sqrt{2}*4=8\sqrt{2}.

Answer: C.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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Re: In the figure above, what is the area of triangular region B   [#permalink] 08 Feb 2014, 01:47
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