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Re: M02-24 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re M02-24 [#permalink]
I think this is a high-quality question and the explanation isn't clear enough, please elaborate. Dont we consider 1 and the no. itself to be a factor in this case (90)
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Re: M02-24 [#permalink]
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Vikramaditya00 wrote:
I think this is a high-quality question and the explanation isn't clear enough, please elaborate. Dont we consider 1 and the no. itself to be a factor in this case (90)

­
Please review the solution carefully:

Determining the Number of Positive Factors of a Positive Integer \(n\):

First, perform the prime factorization of an integer \(n\). Let \(n = p^a * q^b * r^c\), where \(p\), \(q\), and \(r\) are the prime factors of \(n\), and \(a\), \(b\), and \(c\) are their respective powers.

The number of positive factors of \(n\) can be determined by the formula \((a+1)(b+1)(c+1)\). NOTE: This includes 1 and \(n\) itself.

For example, to find the number of positive factors of 450, we first perform its prime factorization: \(450 = 2^1 * 3^2 * 5^2\). The total number of positive factors of 450, including 1 and 450, is \((1+1)(2+1)(2+1) = 18\) positive factors.

According to the above, 90, which is equal to \(2*3^2*5\), has \((1+1)(2+1)(1+1) = 12\) positive factors, namely 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90.


Answer: E­
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