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m23#17

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Re: m23#17 [#permalink] New post 01 Aug 2012, 06:33
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voodoochild wrote:
Bunuel,
I am a bit confused about this question.

If Ay + B = C and A, B and C are known, then there should be only one value of y = (C-B)/A.

1) C>B This should be sufficient because A, B and C are known. Correct? If C = 5, B = 4, A = 2, I will get a unique value of 'y'.

2) A>1 => Again,...All three variables are known. Hence, Sufficient.

I am really not able to follow the OE about #1 - Consider A= 0 and A=1..Why? A,B and C are known...I am lost.

Can you please help me?

Thanks


This question is removed from the set. So, I wouldn't worry about it.
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Quant - Linear equations with parameters [#permalink] New post 01 Aug 2012, 08:16
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Relevant to an old question (was M03-Q23):
m23-74149.html

Consider the the equation Ax=B, where A and B are given real numbers, and x is to be found.
There are three possible scenarios:

1) A\neq0. In this case, the given equation has a unique solution given by \frac{B}{A}. Doesn't matter who is B, it can be also 0, as 0 divided by a non-zero number is 0.
2) A = 0 and B = 0. In this case, the given equation has infinitely many solutions, as for any number x, 0 * x = 0.
3) If A = 0, but B\neq0, then the given equation has no solution, because Ax = 0 * x = 0 \neq{B}.

I hope the above can help when discussing any linear equation with one unknown and parameters (letters instead of numbers as coefficients).
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Quant - Linear equations with parameters   [#permalink] 01 Aug 2012, 08:16
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