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Material A costs $3 per kilogram, and material B costs $5

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gluon
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Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   14 Sep 2007, 12:42
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Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y?

(1) y > 4

(2) The cost of the 10 kilograms of material K is less than $40.



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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   14 Sep 2007, 22:12
gluon wrote:
Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y?

(1) y > 4

(2) The cost of the 10 kilograms of material K is less than $40.


I think B is sufficient.

As per (2),

3x + 5y < 40 -------------- (A)

And as per problem,

x + y = 10

Let's say x > y then,

Possible values of x and y would be (taking only whole numbers)

If x = 6 then y= 4
=> 3x+5y = 38 which is less than 40 so satisfying (A)

If x = 7 then y= 3
=> 3x+5y = 36 which is less than 40 so satisfying (A)

and so on......

Hence B.

- Brajesh
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   14 Sep 2007, 23:52
gluon wrote:
Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y?

(1) y > 4

(2) The cost of the 10 kilograms of material K is less than $40.


S1:

For some reason, maybe its burn out, I can't see why S1 is insuff.

if y>4 then Y must be y>=5 (Assuming X and Y must be integers).

X+Y=10

If Y=5. Then X is not greater than 5 b/c 5+5=10 5not greater than 5.

So. NO

If Y =6 X is not greater than Y... Again NO. However, if we are allowed to say X and Y can be mixed numbers (4.5, 4.6, etc...) then S1 IS insuff.

S2:

3(x)+5(y)<40. So again assuming these must be integers the number 3(x)+5(y) <=to 38. Can't be 39 b/c 3(x)+5(y) (assuming x and y are integers) will never add up to 39 because X+Y must equal 10.

So in this case 3*6+5*4 = 38 X>Y Yes.

Now try to maximize Y w/o exceeding 39.

3(5) +5(5) = too big (15+25=40)
3(4) +5(6) = too big (12+30=42)
3(3) +5(7) = too big (9+35=44)
3(2) +5(8) = too big (6+40 =46) Y must be less than 5 so B is suff.

I say D for this one assuming X and Y have to be integers.

Please let me know about 1. I am a bit braindead right now.



Also 1 last thing. I thougt the statements werent suppose to contradict each other.

S1: y>4? S2: y must be 4 or less???
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   15 Sep 2007, 04:13
Should be 'B'.


Stem says x + y = 10
Stmt1: y > 4
x can be more or less than y. So NOT SUFF
Stmt2: 3x + 5y <40>5
If x greater than 5, then y has to be less than 5
So SUFF.
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   Updated on: 15 Sep 2007, 09:23
Agree with E

Soryy put another comment, for other thread... made a mistake :)

Here I think Ans is B

Originally posted by Ferihere on 15 Sep 2007, 07:08.
Last edited by Ferihere on 15 Sep 2007, 09:23, edited 1 time in total.
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   15 Sep 2007, 07:40
GMATBLACKBELT wrote:
gluon wrote:
Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y?

(1) y > 4

(2) The cost of the 10 kilograms of material K is less than $40.


S1:

For some reason, maybe its burn out, I can't see why S1 is insuff.



(1) is insufficient because of the fact x + y = 10
So if y > 4, then y = 5, x = 5 OR y = 6, x = 4

The OA is B.
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   15 Sep 2007, 10:15
gluon wrote:
GMATBLACKBELT wrote:
gluon wrote:
Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y?

(1) y > 4

(2) The cost of the 10 kilograms of material K is less than $40.


S1:

For some reason, maybe its burn out, I can't see why S1 is insuff.



(1) is insufficient because of the fact x + y = 10
So if y > 4, then y = 5, x = 5 OR y = 6, x = 4

The OA is B.


Exactly as I say in my post. But i still disagree. B/c in both cases you gave I can give a definite NO.

X is not greater than Y in both cases so again why is this not suff?
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   Updated on: 15 Sep 2007, 15:42
GMATBLACKBELT wrote:
Exactly as I say in my post. But i still disagree. B/c in both cases you gave I can give a definite NO.

X is not greater than Y in both cases so again why is this not suff?


Yeah you are right. I gave wrong examples in my answer. We need to consider real numbers, not integers as you pointed out.

It should be:

x + y = 10
(1) if y > 4, then
y = 4.5, x = 5.5 gives y <x> x
Hence, (1) is insufficient.

Originally posted by gluon on 15 Sep 2007, 14:53.
Last edited by gluon on 15 Sep 2007, 15:42, edited 2 times in total.
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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink] New post   15 Sep 2007, 15:22
gluon wrote:
GMATBLACKBELT wrote:
Exactly as I say in my post. But i still disagree. B/c in both cases you gave I can give a definite NO.

X is not greater than Y in both cases so again why is this not suff?


Yeah you are right. I gave wrong examples in my answer. We need to consider real numbers, not integers as you pointed out.

It should be:

x + y = 10
(1) if y > 4, then
y = 4.5, x = 5.5 gives y y
Hence, (1) is insufficient.


lol ok :P whew! I thought I was goin nuts or something.

Thanks



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Re: Material A costs $3 per kilogram, and material B costs $5 [#permalink]
15 Sep 2007, 15:22
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