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Re: Math question probability [#permalink]
nailgmattoefl wrote:
Hello,
Here is the problem:
"At a certain pet stores, 1/3 of the pets are dog, 1/5 are dogs birds, how many of the pets are dog
1) There are 30 birds at the pet shop
2) There are 20 more dogs than birds at the pet shop
The answer was: each statement alone is sufficient
1) ==> Total number of pets = 30 birds x 5 = 150 pets
Number total of dogs = 150 pets/3 = 50 dogs
2) N_dogs = N_birds + 20
=> How this statement is sufficient alone?
Thanks in advance


i think its 1/5 bird well in that case
eqn for s2) is N_dogs=N_birds+20
N_doga=1/3 Pets
N_birds=1/5 pets
--->1/3 pets =1/5 pets+20----> solving pets =150

rest u knw hence its suff

and kindly recheck the q and edit it



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Re: Math question probability [#permalink]
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