Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

On a certain scale of intensity, each increment of 10 in mag [#permalink]
07 Oct 2009, 19:46

1

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

25% (medium)

Question Stats:

72% (01:40) correct
28% (01:02) wrong based on 76 sessions

On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125?

Re: Scale of Intensity [#permalink]
08 Oct 2009, 01:05

amitgovin wrote:

On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125?

A. 40 b. 100 c. 400 d. 1,000 e. 10,000

this seems like it should be straight forward but I think that I'm missing something. please explain. thanks.

Re: Scale of Intensity [#permalink]
08 Oct 2009, 02:00

jax91 wrote:

amitgovin wrote:

On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125?

A. 40 b. 100 c. 400 d. 1,000 e. 10,000

this seems like it should be straight forward but I think that I'm missing something. please explain. thanks.

let 125 be of intensity x

so 125 + 10 =135 = 10x

135 + 10 = 145 = 10 (10x) = 100x

145 + 10 = 155 = 10 (100x) = 1000x

155 + 10 = 165 = 10 (1000x) = 10,000x

can u explain in details _________________

Bhushan S. If you like my post....Consider it for Kudos

On a certain scale of intensity, each increment of 10 in mag [#permalink]
10 Mar 2011, 09:32

On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a amgnitude of 165 is how many times an intensity corresponding to 125?

On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a amgnitude of 165 is how many times an intensity corresponding to 125? A/ 40 B/ 100 C/ 400 D/ 1000 E/ 10 000

Increase of 40 in magnitude corresponds to 10^4 increase in intensity:

If intensity for 125 is x then for 135 it'll be 10*x, for 145 it'll be 10*10*x=10^2*x, for 155 it'll be 10*10*10*x=10^3*x and for 165 it'll be 10*10*10*10*x=10^4*x.

Re: Scale of Intensity [#permalink]
18 Dec 2013, 09:02

amitgovin wrote:

On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125?

A. 40 b. 100 c. 400 d. 1,000 e. 10,000

this seems like it should be straight forward but I think that I'm missing something. please explain. thanks.

Increment of 10 between 165 and 125 is 4

So then the increase in intensity will be 10^4 = 10,000

Re: On a certain scale of intensity, each increment of 10 in mag [#permalink]
27 Feb 2014, 21:17

Is this logic ok? When I looked at this I subtracted 125 from 165 to get 40. Then thinking that this is the difference in the magnitudes and that magnitude gives us how many tenfold to calculate (so we have 4 increments of 10 in the magnitude so that would tell us 10^4) to give us 4 0s in the answer choice.

I think this may be similiar logic to jldgr but I just wanted to confirm. Thanks for the help!

Re: On a certain scale of intensity, each increment of 10 in mag [#permalink]
27 Feb 2014, 22:15

Expert's post

amjet12 wrote:

Is this logic ok? When I looked at this I subtracted 125 from 165 to get 40. Then thinking that this is the difference in the magnitudes and that magnitude gives us how many tenfold to calculate (so we have 4 increments of 10 in the magnitude so that would tell us 10^4) to give us 4 0s in the answer choice.

I think this may be similiar logic to jldgr but I just wanted to confirm. Thanks for the help!