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Out of 8 employees including Bob and Mary, a team of 4

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Senior Manager
Joined: 04 Mar 2007
Posts: 442
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Kudos [?]: 17 [0], given: 0

Out of 8 employees including Bob and Mary, a team of 4 [#permalink]  12 May 2007, 03:18
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100% (01:17) correct 0% (00:00) wrong based on 1 sessions
Out of 8 employees including Bob and Mary, a team of 4 members is to be selected at random. What is the probability that the team will include Mary but exclude Bob?
Manager
Joined: 02 Jan 2007
Posts: 208
Followers: 2

Kudos [?]: 3 [0], given: 0

Senior Manager
Joined: 04 Mar 2007
Posts: 442
Followers: 1

Kudos [?]: 17 [0], given: 0

Thanks.
Didn't find it somehow in my search.
Manager
Joined: 02 Jan 2007
Posts: 208
Followers: 2

Kudos [?]: 3 [0], given: 0

Happens to me all the time .
You seem to be focusing on Perms/Combs & Probability these days.
Are you also using Project GMAT?
Senior Manager
Joined: 04 Mar 2007
Posts: 442
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Kudos [?]: 17 [0], given: 0

No, I don't.
I am just going through the problems which I didn't understand earlier. They are from different GMAT sources.
Yeah, you are right. Combinatorix and probabilities are the hardest topics for me.
Manager
Joined: 13 Feb 2007
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Probability of Selected Team [#permalink]  13 May 2007, 09:02
I believe the probability is 2/7. Start with the prob of getting Mary on the team: 1/8 but you have four shots of getting her on the team since you are picking 4 team members, so this results in 1/2 chance of getting Mary on the team. Next the chance of not getting Bob in the 2nd spot is 6/7, because there are 7 members to choose and from and 1 who we don't want: Bob. Likewise the chance of not getting Bob on the 3rd and 4th selection are 5/6 and 4/5 respectively. This multiplies out to 2/7.
Probability of Selected Team   [#permalink] 13 May 2007, 09:02
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