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In a certain marching band formation
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29 Jun 2013, 03:35
29 Jun 2013, 03:35
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In a certain marching band formation, each row of band members has the same number of members, and the number of rows is 1 less than the number of members in a row. How many band members are there in each row?
(1) There is a total of 90 band members.
(2) If each of the members of the last row were assigned to a different row, the row with the least number of members would have 10 members.
(1) There is a total of 90 band members.
(2) If each of the members of the last row were assigned to a different row, the row with the least number of members would have 10 members.
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Re: In a certain marching band formation
[#permalink]
30 Jun 2013, 12:05
30 Jun 2013, 12:05
It is basically a formation that has 1 row less than the number of members ---> number of rows + 1 = number of members in a row
1) There are 90 members overall - x * (x + 1) = 90 - simply plug in numbers 9 and 10 and voila it is sufficient since there are no alternate solutions. We now know the exact number of rows and members in a row. Alternatively, you could simply use the formula x^2 + x - 90 = 0 and find the solution there. Sufficient
2) A little tricky wording because it almost seems that there could be only one row with the least number of members (in this case 10). But depending on the number of members there could be more rows with 10 members while other rows have more than 10 (i.e. 11). Not sufficient
Answer A
1) There are 90 members overall - x * (x + 1) = 90 - simply plug in numbers 9 and 10 and voila it is sufficient since there are no alternate solutions. We now know the exact number of rows and members in a row. Alternatively, you could simply use the formula x^2 + x - 90 = 0 and find the solution there. Sufficient
2) A little tricky wording because it almost seems that there could be only one row with the least number of members (in this case 10). But depending on the number of members there could be more rows with 10 members while other rows have more than 10 (i.e. 11). Not sufficient
Answer A
Re: In a certain marching band formation
[#permalink]
20 Aug 2013, 21:56
20 Aug 2013, 21:56
Baracuda123 wrote:
It is basically a formation that has 1 row less than the number of members ---> number of rows + 1 = number of members in a row
1) There are 90 members overall - x * (x + 1) = 90 - simply plug in numbers 9 and 10 and voila it is sufficient since there are no alternate solutions. We now know the exact number of rows and members in a row. Alternatively, you could simply use the formula x^2 + x - 90 = 0 and find the solution there. Sufficient
2) A little tricky wording because it almost seems that there could be only one row with the least number of members (in this case 10). But depending on the number of members there could be more rows with 10 members while other rows have more than 10 (i.e. 11). Not sufficient
Answer A
1) There are 90 members overall - x * (x + 1) = 90 - simply plug in numbers 9 and 10 and voila it is sufficient since there are no alternate solutions. We now know the exact number of rows and members in a row. Alternatively, you could simply use the formula x^2 + x - 90 = 0 and find the solution there. Sufficient
2) A little tricky wording because it almost seems that there could be only one row with the least number of members (in this case 10). But depending on the number of members there could be more rows with 10 members while other rows have more than 10 (i.e. 11). Not sufficient
Answer A
To me it seems something is wrong with statement 2 , if all rows are supposed to have the same number of members how can there be a least row and most row? Something seems odd about statement 2
