arslano wrote:
If |x| != |y|, xy != 0,
x/(x+y) = n, and x/(x-y) = m,
then x/y = ?
what i do is, equate the two x and solve
x/(x+y) = n, and x/(x-y) = m, - equation (0)
x=nx+ny ; x=mx-my - equation (1)
on solving above
x/y=(m+n)/(m-n) - equation (2)
i now substitute values for m and n (3,2) and find the value for x/y. The value turns out to be 5.
But when i substitute the same values in the answer choices, none of the them match.
However, if i substitute the values (say 2,3 again) of x and y in equation (0) and find the corresponding values of m and n, and then substitute the values of m and n in the answer choices, the answer matches the value of x/y that i had chosen(2/3).
Im not able to understand why the answers are not matching x/y when i substitute random values of m,n straightaway in equation (2) and why they do so wen i substitute the values of m,n derived from the substituted values of x,y in equation(0)
Can someone please help in trying me understand where i am going wrong .
ANSWER CHOICES
a> 3m/2
b>3m/2n
c>n(m+2)/2
d>2nm/(m-n) This is the right answer
e>n^2-m^2/nm
The problem is that you don't have independent values of m and n. These values are derived from the values of x and y. Depending on the values of x and y, we will get the values of m and n. Due to the relation between x/(x+y) and x(x-y), m and n cannot take every value.
Note that because m and n both depend on x and y, there will be certain relations between them.
e.g. using each equation independently, you get
x/y = n/(1 - n)
x/y = m/(m - 1)
Equating them, you get 2mn = m + n
When you take random values for m and n, these relations may not hold. So if you have to assume values, you have to assume values of the independent variables, not for the dependent variables.
So assume values for x and y and then proceed as shown below.
Say x = 2, y = 1
x/(x+y) = n = 2/3, and x/(x-y) = m = 2
You get x/y = (m+n)/(m-n) = (2+2/3)/(2 - 2/3) = 2
Put m = 2 and n = 2/3 in the options. Option (D) gives you 2.