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Re: The positive integer x has how many different positive [#permalink]
I think D is sufficient.

From one we know that 7^5 is the multiple of 1, 7, ......7^5 ie 6. That is all we need. Am I wrong?

From two we know that the factors are 1, a, b, ab, a^2, a^2b. 6.

Just to validate we are getting 6 from both statements. What is wrong here? :?:
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Re: The positive integer x has how many different positive [#permalink]
I think its D

a) same no oif multiples as 7^5 means (5+1) factors
b) x=a^2*b means (2+1)*(1+1) factods
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Re: The positive integer x has how many different positive [#permalink]
D

St1: there are 6 factors of 7^5. SUFF

St2: Total factors of a^2 *b = (2+1) *(1+1) = 6. SUFF
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Re: The positive integer x has how many different positive [#permalink]
bewakoof wrote:
The positive integer x has how many different positive factors?

1. x is a multiple of the same number of positive integers that 7^5 is

2. x = a^2*b where a and b are different prime numbers.


7^5 is a multiple of 1 and 7

What is 1. paraphrased?

I think:

x= b*1*7

b can therefore be 7 or 7^2 etc.

I go for B



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