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805+ Level|   Math Related|   Tables|         
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Hello Experts,

Need your guidance to solve this question.

chetan2u , KarishmaB , MartyMurray

Regards
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KarishmaB

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­For each of three years and five survey prompts, the table shows the percentage of respondents to a job-satisfaction survey who agreed with the prompt. For columns showing pairs of years in the top row, a minus sign (–) or plus sign (+) for a prompt indicates that the change in the percentage of respondents from the first year to the second represents a significant decrease or significant increase, respectively. For the difference in the number of percentage points to be considered significant, its absolute value must be greater than a certain number, x. Although the percentages in the table are rounded to the nearest percentage point, whether a change is significant is determined using the raw percentages prior to rounding.


For each of the following values, select Could be x if that exact value for x is consistent with the information provided. Otherwise, select Cannot be x.
 ­­
Essentially, the question is testing you on your rounding basics. Diff in percentage points from one year to another was calculated. If it was more than x, a +/- was put. If it was less than x, it was left blank. 
Then the given values in the table were rounded. So each given value, say 63% could actually be anything from 62.5% (including) to 63.5%(excluding).

Focus on the values where the difference is smallest possible but 'significant'.
In 14-15, 82% - 83% is significant. Here the actual difference could be 81.5% to a little less than 83.5%. So the maximum actual difference could be slightly less than 2. So x can be slightly less than 2 but it cannot be 2. If x were 2, then this would have been 'not significant.'

Focus on the values where the difference is largest possible but 'not significant'.
In 14-15, 69% - 70% is not significant­
These could be a little less than 69.5% and 69.5% so the minimum value of x could be very little (slightly more than 0).
Say actual values here could be 69.4% - 69.5%. Then if x = 0.1, even then these would be 'not significant'.

Hence x can easily take very small values so 0.9 and 1.4 are both acceptable. 
­Hi KarishmaB,
Lets Focus on the year 14-15 for Point no 3.

Here values can be 54.5 ( inclusive ) and 57.5 (exclusive)

So the values can be anything between 0 and 3. 

So all the options are possible.

Please guide.

Regards


 
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KarishmaB

Iwillget770
­For each of three years and five survey prompts, the table shows the percentage of respondents to a job-satisfaction survey who agreed with the prompt. For columns showing pairs of years in the top row, a minus sign (–) or plus sign (+) for a prompt indicates that the change in the percentage of respondents from the first year to the second represents a significant decrease or significant increase, respectively. For the difference in the number of percentage points to be considered significant, its absolute value must be greater than a certain number, x. Although the percentages in the table are rounded to the nearest percentage point, whether a change is significant is determined using the raw percentages prior to rounding.


For each of the following values, select Could be x if that exact value for x is consistent with the information provided. Otherwise, select Cannot be x.
 ­­
Essentially, the question is testing you on your rounding basics. Diff in percentage points from one year to another was calculated. If it was more than x, a +/- was put. If it was less than x, it was left blank. 
Then the given values in the table were rounded. So each given value, say 63% could actually be anything from 62.5% (including) to 63.5%(excluding).

Focus on the values where the difference is smallest possible but 'significant'.
In 14-15, 82% - 83% is significant. Here the actual difference could be 81.5% to a little less than 83.5%. So the maximum actual difference could be slightly less than 2. So x can be slightly less than 2 but it cannot be 2. If x were 2, then this would have been 'not significant.'

Focus on the values where the difference is largest possible but 'not significant'.
In 14-15, 69% - 70% is not significant­
These could be a little less than 69.5% and 69.5% so the minimum value of x could be very little (slightly more than 0).
Say actual values here could be 69.4% - 69.5%. Then if x = 0.1, even then these would be 'not significant'.

Hence x can easily take very small values so 0.9 and 1.4 are both acceptable. 
Quote:
­Hi KarishmaB,
Lets Focus on the year 14-15 for Point no 3.

Here values can be 54.5 ( inclusive ) and 57.5 (exclusive)

So the values can be anything between 0 and 3. 

So all the options are possible.

Please guide.

Regards
A possible value of x should work for the entire table. If there is even one reading for which it doesn't work, then that value is not possible. x = 3 does not work for 82% - 83% being significant. If x = 3, this CANNOT be significant and the table becomes false. This is not acceptable.


­­
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Can someone explain the highlighted part to me ? This question is so hard to understand . TargetTestPrep  gmatophobia
KarishmaB

Iwillget770
­For each of three years and five survey prompts, the table shows the percentage of respondents to a job-satisfaction survey who agreed with the prompt. For columns showing pairs of years in the top row, a minus sign (–) or plus sign (+) for a prompt indicates that the change in the percentage of respondents from the first year to the second represents a significant decrease or significant increase, respectively. For the difference in the number of percentage points to be considered significant, its absolute value must be greater than a certain number, x. Although the percentages in the table are rounded to the nearest percentage point, whether a change is significant is determined using the raw percentages prior to rounding.


For each of the following values, select Could be x if that exact value for x is consistent with the information provided. Otherwise, select Cannot be x.
 ­
Essentially, the question is testing you on your rounding basics. Diff in percentage points from one year to another was calculated. If it was more than x, a +/- was put. If it was less than x, it was left blank. 
Then the given values in the table were rounded. So each given value, say 63% could actually be anything from 62.5% (including) to 63.5%(excluding).

Focus on the values where the difference is smallest possible but 'significant'.
In 14-15, 82% - 83% is significant. Here the actual difference could be 81.5% to a little less than 83.5%. So the maximum actual difference could be slightly less than 2. So x can be slightly less than 2 but it cannot be 2. If x were 2, then this would have been 'not significant.'

Focus on the values where the difference is largest possible but 'not significant'.
In 14-15, 69% - 70% is not significant­
These could be a little less than 69.5% and 69.5% so the minimum value of x could be very little (slightly more than 0).
Say actual values here could be 69.4% - 69.5%. Then if x = 0.1, even then these would be 'not significant'.

Hence x can easily take very small values so 0.9 and 1.4 are both acceptable. 
­
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Few things to notice in this ques:
1.If we look in the table carefully only prompt 5 has both + and - signs which means that the difference in both the cases is significant.
2. It is a could be true question so the answer need not be true in every scenario, so if we can pick one prompt and can get most of our answer it would work for us.

Now, if we check for min and max difference in both the cases with minimum value of 2014 figure we'll get an idea
Min(84-82)=1.1 ------>(83.5-82.4) [Note same would be value of 82 when using it for '14 '15 difference]
Max(84-82) = 2.9 ------>(84.4-81.5) [Note same would be value of 82 when using it for '14 '15 difference]

Min(83-82)= 0.1 (82.5-82.4)
Max(83-82)= 1.9(83.4-81.5)

Case:1
When 82 is min then values are 1.1&0.1(Any value less than 1.1&0.1 could be the value of X hence 0.9can be the value of X)
Case:2
When 82 is max then values are 2.9&1.9 (Any value less than 2.9&1.9 could be the value of X hence 1.4can be the value of X)
Rest in all cases when we'll be satisfying values one part will always be greater than 2 as in Case:2
Hence, 2 cannot be the value of x

chetan2u KarishmaB Bunuel any suggestion for this approach
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I did not understand the question at first. Even after making an attempt with the online question bank I ended up spending 4 mins and 46 seconds, not sure the question was clear enough for me.

I am wondering if I am missing anything or the question has some ambiguity if you are doing it for the first time...
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The max value for rounding is +0.4999, while the least is 0.


Difference Min    Max
               70     70.49
Min 69      1       1.49
Max 69.49 0.51    1­         

The answer could range from 0.51 to 1.49. Here 2 is the only option that does not fit
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KarishmaB

Iwillget770
­For each of three years and five survey prompts, the table shows the percentage of respondents to a job-satisfaction survey who agreed with the prompt. For columns showing pairs of years in the top row, a minus sign (–) or plus sign (+) for a prompt indicates that the change in the percentage of respondents from the first year to the second represents a significant decrease or significant increase, respectively. For the difference in the number of percentage points to be considered significant, its absolute value must be greater than a certain number, x. Although the percentages in the table are rounded to the nearest percentage point, whether a change is significant is determined using the raw percentages prior to rounding.


For each of the following values, select Could be x if that exact value for x is consistent with the information provided. Otherwise, select Cannot be x.
­
Essentially, the question is testing you on your rounding basics. Diff in percentage points from one year to another was calculated. If it was more than x, a +/- was put. If it was less than x, it was left blank.
Then the given values in the table were rounded. So each given value, say 63% could actually be anything from 62.5% (including) to 63.5%(excluding).

Focus on the values where the difference is smallest possible but 'significant'.
In 14-15, 82% - 83% is significant. Here the actual difference could be 81.5% to a little less than 83.5%. So the maximum actual difference could be slightly less than 2. So x can be slightly less than 2 but it cannot be 2. If x were 2, then this would have been 'not significant.'

Focus on the values where the difference is largest possible but 'not significant'.
In 14-15, 69% - 70% is not significant­
These could be a little less than 69.5% and 69.5% so the minimum value of x could be very little (slightly more than 0).
Say actual values here could be 69.4% - 69.5%. Then if x = 0.1, even then these would be 'not significant'.

Hence x can easily take very small values so 0.9 and 1.4 are both acceptable.
­

How come the year 2013 is not being considered when determiningdifference in percentage points?
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egmat pls make a video solution- this wording and the ask is totally not clear. What is the role of significant? why is max possible difference between 69 and 70.­ What is absolute value here- non percentage value or non negative value of the percent difference­

KarishmaB can ou explain your approach more as to why you have chosen those differences and how they relate tot the question asked. If difference cant be 2 then how come we hvae values in the table where difference is easily coming to be 2?­
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x is an absolute value used as a threshold to decide whether an absolute difference in percentages is significant or insignificant, which means
1) We’re trying to find the min value of x, beyond which the difference is significant
2) This also means we’re trying to find the max value of x, below which the difference is insignificant

For the first part, look for values where difference of rounded off values is min but was still considered significant.
This is row 5, column 2014-2015 where values are a = 83 & b = 84, this implies actual values of
82.5 =< a < 83.5
83.5 =< b < 84.5
To get the min of x, subtract max a from min b (since we’re dealing with absolute values, we’re subtracting smaller numbers from bigger numbers throughout)
To get the max of x, subtract min a from max b
Therefore 0 < x < 2 ( important to note, x is not 0 and not 2)

For the second part, look for values where difference of rounded off values is max but was still considered insignificant.
This is row 2, column 2014-2015 where values are c = 69 & d = 70, this implies actual values of
68.5 =< c < 69.5
69.5 =< d < 70.5
To get the min of x, subtract max c from min d
To get the max of x, subtract min c from max d
Therefore 0 < x < 2 ( important to note, x is not 0 and not 2)

From both these statements, we arrive at the conclusion that x could be a value strictly greater than 0 and strictly less than 2.

Now looking at answers, any option that lies in this range could be x and satisfy all data points in the table. Answer is Y, Y, N.

Additional explanation:
We cannot narrow down further based on the data given in the table. The only reason we checked for the second condition above is to find whether we can narrow down our range from the first condition (for example if d = 71 instead of 70 then 1 < x < 3 which combined with first would have given us 1 < x < 2).

We could have also skipped calculations for step 2, because the difference in rounded off values that are considered significant and insignificant are the same they would yield the same range of 0 to 2 (both not included).

A quick shortcut here is since values are rounded off within a range of 1 unit (slightly less than 1), we directly obtain the range by adding and subtracting 1 from the difference of rounded off values. Just be careful here to note that both extreme values are not included since range is slightly less than 1. If you are uncomfortable with this shortcut, above steps will always result in correct ranges.

To help understand the solution better, let’s assume a really small value of x and check for the above two data points. If it can satisfy these two it will satisfy any other data point.
For example Say x = 0.001, then possible values of a = 83.49, b = 83.5 meaning difference = 0.01 > x
And also c = 69.4999 and d = 69.5 meaning difference = 0.0001 < x

Even though you might consider a difference of 0.001 insignificant, we have no information on whether the author considers it significant or insignificant. We also have no information on the specific actual values so they could be anything within their own ranges that satisfy all the conditions. Therefore all values of 0 < x < 2 could be possible answers.

Here’s another example from the answer options, x = 1.4
Then possible values of a = 82.52, b = 84.13 meaning difference = 1.61 > x
and also c = 68.5 and d = 69.69 meaning difference = 1.19 < x
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Alright this is a fun question. Definitely not easy, if you're seeing it for the first time, but definitely possible to solve.

Solution - As per the solution of other's who have already pointed it out, for a difference of 1% between two columns, the range of values due to rounding error will be between 0 and 2. Extending the same principle for other values you get.

DifferenceRange
-1-2 < p < 1
0-1 < p < 1
10 < p < 2
21 < p < 3
32 < p < 4

Here "p" represents the actual percentage difference.

Just focusing on the values in the 2014-15 column with significant difference, we get the following for the possible ranges for the percentage difference.

0 < p < 2 and 1 < p < 3.

The value of "x" to be chosen needs to be consistent with the value ranges of "p" such that "p" is significant as per the original table.

Therefore, the possible value range of x, would look like;

0 < x < p < 2.
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For 2013 to 2014, in Line 2, 2013 can be 71.5 and 2014 can be 69.4 which gives value of 2.1? Why is x = 2 not possible then?
KarishmaB

Essentially, the question is testing you on your rounding basics. Diff in percentage points from one year to another was calculated. If it was more than x, a +/- was put. If it was less than x, it was left blank.
Then the given values in the table were rounded. So each given value, say 63% could actually be anything from 62.5% (including) to 63.5%(excluding).

Focus on the values where the difference is smallest possible but 'significant'.
In 14-15, 82% - 83% is significant. Here the actual difference could be 81.5% to a little less than 83.5%. So the maximum actual difference could be slightly less than 2. So x can be slightly less than 2 but it cannot be 2. If x were 2, then this would have been 'not significant.'

Focus on the values where the difference is largest possible but 'not significant'.
In 14-15, 69% - 70% is not significant­
These could be a little less than 69.5% and 69.5% so the minimum value of x could be very little (slightly more than 0).
Say actual values here could be 69.4% - 69.5%. Then if x = 0.1, even then these would be 'not significant'.

Hence x can easily take very small values so 0.9 and 1.4 are both acceptable.
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For 2013 to 2014, in Line 2, 2013 can be 71.5 and 2014 can be 69.4 which gives value of 2.1? Why is x = 2 not possible then?

Your 71.5 and 69.4 example makes that one row significant even if x = 2, but x must fit all rows at once. In 2014 to 2015 for prompt 5, the table shows 82 to 83 and it is marked significant. The largest raw difference consistent with rounding there is under 2, for example 83.49 minus 81.51 equals 1.98. Since it is significant, x must be less than 2. Hence x = 2 is impossible.
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