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TRY this one_PS_Percent_exceeding speed

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IrinaOK
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TRY this one_PS_Percent_exceeding speed [#permalink] New post   03 Sep 2007, 23:08
00:00
A
B
C
D
E

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(N/A)

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will provide with answer later, plz explain

sorry about fuzzy image...



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Whatever
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post   03 Sep 2007, 23:46
I would answer 30 =)

Total = 100, some exceed, some - do not
From exceeding:
10 = exceeded + ticketed
20 = exceeded + not ticketed

This is my logic.

P.S> Sound like my favorite CR =)
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post   04 Sep 2007, 00:23
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


its very confusing.

= 10%/(100-20)%

= 12.5%
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IrinaOK
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post   04 Sep 2007, 00:37
Fistail wrote:
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


its very confusing.

= 10%/(100-20)%

= 12.5%


nothing is more confusing than answer without explanation............
:=(

no answer would be worse, though...
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IrinaOK
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post   04 Sep 2007, 00:50
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


here, I got it,

let`s say
N-total number of motorists
X-total number of those who exceed the speed limit
then,
0,1N=0,8X
X=0,1/0,8=0,125 or 12,5 percent

0,8=1-0,2

Point here is to stay clear about total number of motorists and those who exceed...

Thank you, Fistail!
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post   04 Sep 2007, 01:05
Here's how you solve it.
Attachments

table.jpg
table.jpg [ 45.66 KiB | Viewed 877 times ]

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Fistail
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post   04 Sep 2007, 08:08
there you go.
:-D


IrinaOK wrote:
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


here, I got it,

let`s say
N-total number of motorists
X-total number of those who exceed the speed limit
then,
0.1N=0.8X
X=0.1/0.8=0.125 or 12.5 percent

0.8=1-0.2

Point here is to stay clear about total number of motorists and those who exceed...

Thank you, Fistail!




Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: TRY this one_PS_Percent_exceeding speed [#permalink]
04 Sep 2007, 08:08
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