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This was my first problem in quant section when I took test

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yash500
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This was my first problem in quant section when I took test [#permalink] New post   22 Oct 2007, 03:54
This was my first problem in quant section when I took test y'day and I could not solve it. Right now I don't remember choices but I will find it out -

2 ^ 5 + 2^ 5 + 3 ^ 5 + 3 ^ 5 + 3 ^ 5 =?



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Re: This was my first problem in quant section when I took test [#permalink] New post   22 Oct 2007, 04:02
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2^5 + 2^5 + 3^5 + 3^5 + 3^5
= x + x + y + y + y where x=2^5 and y=3^5
= x*(1+1) + y*(1+1+1)
= 2*x + 3*y
= 2*2^5 + 3*3^5
= 2^6 + 3^6

Detailed and showing the trick involved behind this GMAT question ;)
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Re: This was my first problem in quant section when I took test [#permalink] New post   22 Oct 2007, 22:09
yash500 wrote:
This was my first problem in quant section when I took test y'day and I could not solve it. Right now I don't remember choices but I will find it out -

2 ^ 5 + 2^ 5 + 3 ^ 5 + 3 ^ 5 + 3 ^ 5 =?


2^5+2^5 --> 2(2^5) --> 2^6

same logic for 3^5.

u get 2^6+3^6. To solve further ur gunna have to multiply. But u should know at least that 2^5=32 so 2^6 is 64.

and u should know that 3^4=81. So 3^6=729.

64+729=793.
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Re: This was my first problem in quant section when I took test [#permalink] New post   23 Oct 2007, 02:07
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2^5 + 2^5 + 3^5 + 3^5 + 3^5 =?

2(2^5) + 3(3^5)

2^6 + 3^6
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Re: This was my first problem in quant section when I took test [#permalink] New post   23 Oct 2007, 02:48
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ywilfred wrote:
2^5 + 2^5 + 3^5 + 3^5 + 3^5 =?

2(2^5) + 3(3^5)

2^6 + 3^6


I also solved same like u guys have solved but their answers were again in terms of power. I try to get that question again but could not get it. I think I have to give some more try.

But I remember, in answer choices
2 ^ 7 + something - was their answer which I could not get it.



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Re: This was my first problem in quant section when I took test [#permalink]
23 Oct 2007, 02:48
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