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Re: Is line Y=KX + B tangent to circle X^2 + Y^2 = 1 ? 1. k+b=1 [#permalink]
Ok.. found something that could be useful

formula to calculate pependicular distance from a point, say (p,q), to a line defined by ax+by+c=0 is

d = (ap+bq+c)/sqrt(a^2+b^2)

plug in (0,0) for (p,q) and 1 for d => B^2-K^2=1

Both statement 1 and 2 cannot be infered from the above equation. So still sticking to E.
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Re: Is line Y=KX + B tangent to circle X^2 + Y^2 = 1 ? 1. k+b=1 [#permalink]
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E

\(X^2 + Y^2 = 1\) - is a circle that intersects Y-axis in points (0,1), (0,-1) and intersects X-axis in points (1,0), (-1,0).

Consider two edge examples that satisfy both conditions:
k=1; b=0 - y=x does not tangent to circle (intersects it)
k=0; b=1; - y=1 tangents to circle in the point (0,1).

Therefore, E
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Re: Is line Y=KX + B tangent to circle X^2 + Y^2 = 1 ? 1. k+b=1 [#permalink]
Walker , I have come under the assumption that intersect can also be tangent. Is that correct?
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Re: Is line Y=KX + B tangent to circle X^2 + Y^2 = 1 ? 1. k+b=1 [#permalink]
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terp26 wrote:
Walker , I have come under the assumption that intersect can also be tangent. Is that correct?


https://en.wikipedia.org/wiki/Circle
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200px-CIRCLE_LINES_2.svg.png
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Re: Is line Y=KX + B tangent to circle X^2 + Y^2 = 1 ? 1. k+b=1 [#permalink]
I agree its E ..

If either K or B =0

if k=1 then its not tangent

if b=1 then it is tangent..



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