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Re: Pls need your quick way [#permalink]
sondenso wrote:
Pls need your quick way!


Just realize that the first is solvable. Yes if you solve it. You get r=10.

But no reason to.


Stmt2: there are numerous values. Try 8 for r.

We get the solution as 1.1664>1.15. Thus we can have many values.

Insuff.
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Re: Pls need your quick way [#permalink]
GMATBLACKBELT wrote:
sondenso wrote:
Pls need your quick way!


Just realize that the first is solvable. Yes if you solve it. You get r=10.

But no reason to.


Stmt2: there are numerous values. Try 8 for r.

We get the solution as 1.1664>1.15. Thus we can have many values.

Insuff.



everyone cracked the first one , for second statement I will use this approach which I think is quicker

(1+r/100)^2 > 1.15


expanding the left side and representing the right side to match the left side will make it much easier
(1 + 2r/100 + r^2/10000) > 1 + 15/100


r^2/10000 is way too small so ignore that term , you can think of the above statement as

(1 + 2r/100 ) > 1 + 15/100

which means 2r> 15 and r>7.5 (not > 8) , so insuff ....
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Re: Pls need your quick way [#permalink]
rpmodi wrote:
r^2/10000 is way too small so ignore that term ,


I really like this evaluation. Thanks rpmodi!



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