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Speed Problem 2

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gmatt14
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Speed Problem 2 [#permalink] New post   25 Apr 2010, 09:02
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Hi all.

A man travels 75% of the way from point A to point B traveling at a speed of 50mph. How fast must he travel the rest of the trip in order to maintain an overall average speed of 40 mph?

Correct Answer: 25

Any suggestions?



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Re: Speed Problem 2 [#permalink] New post   25 Apr 2010, 09:06
opps ... it seems you don't want to use the spoiler at all.. :-) please don't display the answer with the post . take the interest away to solve the problem.
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Re: Speed Problem 2 [#permalink] New post   25 Apr 2010, 09:07
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gmatt14 wrote:
Hi all.

A man travels 75% of the way from point A to point B traveling at a speed of 50mph. How fast must he travel the rest of the trip in order to maintain an overall average speed of 40 mph?

Correct Answer: 25

Any suggestions?


Assume distance between A and B is 200 miles(i assumed this because its the LCM of 40 and 50).

So if average speed needs to be 40 then time = 200/40 = 5 hrs

75% was traveled at 50 miles/hr, so time taken was = 75%*200/50 = 150/50 = 3 hrs.

So you have 5-3 = hrs to travel the remaining distance(200-150 = 50 miles)

Time taken = distance remaining/time remaining = 50/2 = 25 mi/hr

Cheers
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Re: Speed Problem 2 [#permalink] New post   25 Apr 2010, 09:26
Thx a lot Silvers.

@ msand: kk. I'll keep that in mind, not giving away the right answer right away. ;-)
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Re: Speed Problem 2 [#permalink] New post   25 Apr 2010, 09:29
@gmatt14,

This will be good. Post the answers after some posts.
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Re: Speed Problem 2 [#permalink] New post   25 Apr 2010, 09:42
gmatt14 wrote:
Thx a lot Silvers.

@ msand: kk. I'll keep that in mind, not giving away the right answer right away. ;-)


Thanks buddy ....
giving it a try ...
Let's assume distance = 100 m.
75 m is travelled in 50 mph. time taken = 75/50 h
let's assume , rest 25 m is travelled in x mph. time taken = 25/x.
Now, given that 100 / [ (75/50) + (25/x) ] = 40.
therefore , solving x = 25.

I guess there could be some other quicker way of solving this.
This is looking like an weighted avg problem - din't able to apply though.



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Re: Speed Problem 2 [#permalink]
25 Apr 2010, 09:42
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