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Probability Question - Not from a book (No official answer)

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Probability Question - Not from a book (No official answer) [#permalink] New post   07 May 2010, 09:42
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Hey guys - long time lurker here and this is my first post.

My buddy at work was talking about how he plays a lottery where you pick 4 numbers and there is a drawing everyday, which got me thinking about it in terms of the gmat.

Probability of hitting the 4 numbers in order = 1 / 10^4 = 1/10,000 ?

But you can also "win the lottery" if you pick the 4 numbers correctly, not neccesarily in order.

I'm having a little trouble caluclating that number so if you all can help me understand that would be SUPER!

-Sameer



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Re: Probability Question - Not from a book (No official answer) [#permalink] New post   10 May 2010, 06:34
Guys come on!!

I thought we were friends!!!!!
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Re: Probability Question - Not from a book (No official answer) [#permalink] New post   10 May 2010, 07:07
sameermunshi wrote:
Hey guys - long time lurker here and this is my first post.

My buddy at work was talking about how he plays a lottery where you pick 4 numbers and there is a drawing everyday, which got me thinking about it in terms of the gmat.

Probability of hitting the 4 numbers in order = 1 / 10^4 = 1/10,000 ?

But you can also "win the lottery" if you pick the 4 numbers correctly, not neccesarily in order.

I'm having a little trouble caluclating that number so if you all can help me understand that would be SUPER!

-Sameer

Okay, even though I am not an expert but let me give a shot to this one...!

So 4 numbers to choose from ..

so the probability for the 1st number on our lottery ( 4/10 ) because we have 4 numbers to choose from-- assuming we are talking about digits(0-9) here

for 2nd number it should 3/10 and similarly for 3rd number 2/10

So final probablity = \(\frac{(4 *3*2*1)}{10*10*10*10}\)

Cheers,
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Re: Probability Question - Not from a book (No official answer) [#permalink] New post   10 May 2010, 12:12
Thanks Nitish!

So quick question:

if 4*3*2*1 /10*10*10*10 = Prob of picking 4 numbers (order doesnt matter) out of 10

what would 4*4*4*4 / 10*10*10*10 mean? ?

Anyone else have any input?

Appreciate it!!
nitishmahajan wrote:
sameermunshi wrote:
Hey guys - long time lurker here and this is my first post.

My buddy at work was talking about how he plays a lottery where you pick 4 numbers and there is a drawing everyday, which got me thinking about it in terms of the gmat.

Probability of hitting the 4 numbers in order = 1 / 10^4 = 1/10,000 ?

But you can also "win the lottery" if you pick the 4 numbers correctly, not neccesarily in order.

I'm having a little trouble caluclating that number so if you all can help me understand that would be SUPER!

-Sameer

Okay, even though I am not an expert but let me give a shot to this one...!

So 4 numbers to choose from ..

so the probability for the 1st number on our lottery ( 4/10 ) because we have 4 numbers to choose from-- assuming we are talking about digits(0-9) here

for 2nd number it should 3/10 and similarly for 3rd number 2/10

So final probablity = \(\frac{(4 *3*2*1)}{10*10*10*10}\)

Cheers,
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Re: Probability Question - Not from a book (No official answer) [#permalink] New post   10 May 2010, 12:27
sameermunshi wrote:
Thanks Nitish!

So quick question:

if 4*3*2*1 /10*10*10*10 = Prob of picking 4 numbers (order doesnt matter) out of 10

what would 4*4*4*4 / 10*10*10*10 mean? ?

Anyone else have any input?

Appreciate it!!
nitishmahajan wrote:
sameermunshi wrote:
Hey guys - long time lurker here and this is my first post.

My buddy at work was talking about how he plays a lottery where you pick 4 numbers and there is a drawing everyday, which got me thinking about it in terms of the gmat.

Probability of hitting the 4 numbers in order = 1 / 10^4 = 1/10,000 ?

But you can also "win the lottery" if you pick the 4 numbers correctly, not neccesarily in order.

I'm having a little trouble caluclating that number so if you all can help me understand that would be SUPER!

-Sameer

Okay, even though I am not an expert but let me give a shot to this one...!

So 4 numbers to choose from ..

so the probability for the 1st number on our lottery ( 4/10 ) because we have 4 numbers to choose from-- assuming we are talking about digits(0-9) here

for 2nd number it should 3/10 and similarly for 3rd number 2/10

So final probablity = \(\frac{(4 *3*2*1)}{10*10*10*10}\)

Cheers,


Well, Say for e.g the case would have been that we need to pick 4 numbers in any order and at any place holder.

For e.g winning lottery number would have been 4678 and so the condition would have been something like 4 numbers
any order like 4468 or may be even 6777 ( I mean to say any number can fit any where even with repetition then

\frac{4*4*4*4}{10*10*10*10}\(\)

Would have fit the bill...!

Cheers
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Re: Probability Question - Not from a book (No official answer) [#permalink] New post   10 May 2010, 13:18
Is my understanding wrong??

You have 10 digits from 0 to 9 inclusive. You are selecting one number from the 10 for every place, thus you select 4 times to get a four digit number - (10C1)^4 = 10 * 10 * 10 * 10 = 10000.

All possible 4 digit numbers - 9 * 10 * 10 * 10 = 9000 (have to give up 0 for the first spot).

Probability of choosing a 4 digit number from the entire lot = 10000/9000 = 10/9 > 1.

Is this even possible? what am I doing wrong with the question??



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: Probability Question - Not from a book (No official answer) [#permalink]
10 May 2010, 13:18
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