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M01#07

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shrive555
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M01#07 [#permalink] New post   29 Apr 2011, 19:27
A ship is transporting several cats and a crew (sailors, a cook, and a one-legged captain) to a nearby port. If these passengers combined have 15 heads and 41 legs, then how many cats is the ship transporting?

We can make equation like

4C + 2S = 38 => 2C + S = 18 ------ (1)
&
C + S = 13 ------ (2)

subtracting 2 from 1

2C+S =18
-C - S = -13
------------
C = 5
But answer is 6. Can someone please guide me as where i'm making a mistake :roll:
Regards

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gmat1220
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Re: M01#07 [#permalink] New post   29 Apr 2011, 21:43
1
Kudos
15 = cats + crew ------(1)
41 = 4 cats + (2crew - 1) This means cats have 4 legs. Each crew has 2 legs except the captain, so subtract 1
or
42 = 4cats + 2crew ------(2)

Multiply (1) by 2 =>
30 = 2cats + 2crew ------(3)
Subtracting (3) from (2) we get -
12 = 2 cats
cats =6

shrive555 wrote:
A ship is transporting several cats and a crew (sailors, a cook, and a one-legged captain) to a nearby port. If these passengers combined have 15 heads and 41 legs, then how many cats is the ship transporting?

We can make equation like

4C + 2S = 38 => 2C + S = 18 ------ (1)
&
C + S = 13 ------ (2)

subtracting 2 from 1

2C+S =18
-C - S = -13
------------
C = 5
But answer is 6. Can someone please guide me as where i'm making a mistake :roll:
Regards
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shrive555
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Posts: 207
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Re: M01#07 [#permalink] New post   03 May 2011, 08:18
Thanks Gmat1220

i made a stupid mistake :@
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n2739178
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Re: M01#07 [#permalink] New post   25 Sep 2011, 03:40
2
Kudos
answer in the attachments...

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Re: M01#07 [#permalink]
25 Sep 2011, 03:40
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