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Senior Manager
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15 Dec 2005, 14:59
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15 Dec 2005, 20:15
This Q has been posted a lot of times. Hot one...huh?!

h(100)+1 = (2.4.6...100)+1 = 2(1.2.3...50)+1
All prime factors less than 50 will yield a remainder of 1. So nothing less than 50 can be a factor of h(100)+1. Hence E.
15 Dec 2005, 20:15
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