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Re: Set A consists of integers -9, 8, 3, 10, and J; Set B consists [#permalink]
As its given that J is negative, R = 3
34 = 17 * 2
As W is a mode of B => T has to take any one of the values from B.
No other value except T = 0 will make R^W|34.
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Re: Set A consists of integers -9, 8, 3, 10, and J; Set B consists [#permalink]
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uday1409 wrote:
Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and T. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of T if J is negative?

(A) -2
(B) 0
(C) 1
(D) 2
(E) 5


A = { -9, 3, 8, 10, J }
Median R
J is negative so we have 2 negative numbers. Hence, median must be 3.
R = 3

B = { -2, 5, 0, 7, -6, T }
Mode W (this means one of the known 5 numbers is the value of T and that is the mode W)

Factors of 34 = 1, 2, 17, 34
3^W is one of these numbers. W has to be 0 because only 3^0 = 1 is a possible factor.
T = W = 0

Answer (B)
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Re: Set A consists of integers -9, 8, 3, 10, and J; Set B consists [#permalink]
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Re: Set A consists of integers -9, 8, 3, 10, and J; Set B consists [#permalink]
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