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Re: Standard Deviation [#permalink]
SD = Sqrt[(m-x1)^2 + (m-x2)^2 + ... + (m-x100)^2]/100

where m = average(mean) i.e. 6

Now 6, 6 is the only which adds nothing to numerator but now that the demoninator is greater we have our new SD < d (original one)

So, E.
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Re: Standard Deviation [#permalink]
E - although almost seems a bit too obvious!
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Re: Standard Deviation [#permalink]
Most of the SD questions don't test the formula, but the concept of spread or "swing" from the mean/average. It is a little about common sense about the spread when you look at the numbers, so you can judge whether it widens or narrows.



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