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The first 3 terms of a sequence are 2, 7, 22. After the 1st

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Senior Manager
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The first 3 terms of a sequence are 2, 7, 22. After the 1st [#permalink] New post 09 Jul 2007, 18:49
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The first 3 terms of a sequence are 2, 7, 22. After the 1st term, each consecutive can be obtained by multiplying the previous term by 3 and then adding 1. What is the sum of the tens digit and the units digit of the 35th term in the sequence?
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Re: 800 score PS- sequence [#permalink] New post 09 Jul 2007, 18:57
r019h wrote:
The first 3 terms of a sequence are 2, 7, 22. After the 1st term, each consecutive can be obtained by multiplying the previous term by 3 and then adding 1. What is the sum of the tens digit and the units digit of the 35th term in the sequence?


There is a cycle for every four number: 2,7,22,67; 202,607,1822,5467

Therefore the sum of tens digit and the unit digit of the 35th = 3th

2+2=4
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 [#permalink] New post 09 Jul 2007, 19:02
1st term: 0002
2nd term: 0007
3rd term: 0022
4th term: 0067
5th term: 0202
6th term: 0607
7th term: 1822
8th term: 5467

so the units digit toggle between 2 and 7
the tens digit toggle in this manner -> 0,0,2,6,0,0,2,6,.....

35th term: units digit = 2, tens digit =2. Sum = 4.
  [#permalink] 09 Jul 2007, 19:02
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The first 3 terms of a sequence are 2, 7, 22. After the 1st

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