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Re: The units digit of (44^91)*(73^37) is: [#permalink]
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Bunuel wrote:
The units digit of (44^91)*(73^37) is:

(A) 2
(B) 4
(C) 6
(D) 8
(E) 0

Kudos for a correct solution.


MAGOOSH OFFICIAL SOLUTION:

We have to figure out each piece separately, and then multiply them. The powers of 4 are particularly easy.

4^1 has a units digit of 4
4^2 has a units digit of 6 (e.g. 4*4 = 16)
4^3 has a units digit of 4 (e.g. 4*6 = 24)
4^4 has a units digit of 6
4^5 has a units digit of 4
4^6 has a units digit of 6

Four to any odd power will have a units digit of 4. Thus, any number with a units digit of four, raised to an odd power, will also have a units digit of 4. The first factor, 44^91, has a units digit of 4.

Now, the base in the second factor ends in a 3 (we can ignore the tens digit). Here is the pattern for powers of three.

3^1 has a units digit of 3
3^2 has a units digit of 9
3^3 has a units digit of 7 (e.g. 3*9 = 27)
3^4 has a units digit of 1 (e.g. 3*7 = 21)
3^5 has a units digit of 3
3^6 has a units digit of 9
3^7 has a units digit of 7
3^8 has a units digit of 1

The period is 4. This means, 3 to the power of any multiple of 4 will have a units digit of 1.

3^36 has a units digit of 1
3^37 has a units digit of 3

Thus, any number with a units digit of 7, when raised to the power of 37, will have a units digit of 3. The second factor, 73^37, has a units digit of 3.

Of course, 4*3 = 12, so any number with a units digit of 4 times any number with a units digit of 3 will yield a product with a units digit of 2.

Answer = A
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Re: The units digit of (44^91)*(73^37) is: [#permalink]
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Re: The units digit of (44^91)*(73^37) is: [#permalink]
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