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There are 60 cars in a shop. these cars are either full size

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hallelujah1234
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There are 60 cars in a shop. these cars are either full size [#permalink] New post   16 May 2004, 12:08
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A
B
C
D
E

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There are 60 cars in a shop. these cars are either full size or midsize or compact. 10 cars are red and 19 are blue. How many cars are full size?
1) No red or blue cars are of full size
2) The number of full size cars is greater than the sum of mid size
and compact cars



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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   16 May 2004, 19:35
E it is for me.

A) not sufficient because other 31 cars could be compact/midsize/fullsize
B) Not sufficient

If you combine both we know that 10+19 = 29 cars not full size. There are 31 cars left. SO no of full size has to be either 30 or 31. So we cannot determine
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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   17 May 2004, 05:52
anandnk,

I think you might have been hasty in reaching your answer.

I believe the answer is C.

1) Insufficient

2) Insufficient


Reading 1 & 2 together, ----> F > M+C AND F <= 31

For F to be greater than M + C; F must be 31. If F = 30, then it isn't greater than M + C.
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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   17 May 2004, 06:05
ndidi204 wrote:
anandnk,

I think you might have been hasty in reaching your answer.

I believe the answer is C.

1) Insufficient

2) Insufficient


Reading 1 & 2 together, ----> F > M+C AND F <= 31

For F to be greater than M + C; F must be 31. If F = 30, then it isn't greater than M + C.


we know M+C>=29. F could be eiter 30 or 31. Right?
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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   Updated on: 17 May 2004, 08:31
Yes.

But when you combine the two statements, then you're assuming that F > M + C. So F <> 30. F can only be 31.

Originally posted by Makky07 on 17 May 2004, 06:12.
Last edited by Makky07 on 17 May 2004, 08:31, edited 1 time in total.
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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   17 May 2004, 08:13
ndidi204 wrote:
Yes.

But when you combine the two statement, then you're assuming that F > M + C. So F <> 30. F can only be 31.


See M+C could be 29 or greater than 29. This makes F either 30 or 31. Right?
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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   17 May 2004, 08:32
mirhaque , second statment says that number of fullsize is greater than mid/comp so number of fullsize cars has to be greater than 30
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Re: There are 60 cars in a shop. these cars are either full size [#permalink] New post   17 May 2004, 13:46
ndidi204 wrote:
anandnk,

I think you might have been hasty in reaching your answer.

I believe the answer is C.

1) Insufficient

2) Insufficient


Reading 1 & 2 together, ----> F > M+C AND F 29 & F>m+c. how can we say
Quote:
F must be 31




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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: There are 60 cars in a shop. these cars are either full size [#permalink]
17 May 2004, 13:46
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