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Re: There are 8 TV sets, 6 are color and 2 are black-white. If 2 [#permalink]
conocieur wrote:
joemama142000 wrote:
There are 8 TV sets, 6 are color and 2 are black-white. If 2 sets are selected at random, what is the probability that at least one of them is color set?


1 - (2c2 / 8c2)

= 27/28


i'm going a lil crazy, but what is 2c2 again?? ..

i had a totally different solution
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Re: There are 8 TV sets, 6 are color and 2 are black-white. If 2 [#permalink]
Angela780 wrote:
conocieur wrote:
joemama142000 wrote:
There are 8 TV sets, 6 are color and 2 are black-white. If 2 sets are selected at random, what is the probability that at least one of them is color set?


1 - (2c2 / 8c2)

= 27/28


i'm going a lil crazy, but what is 2c2 again?? ..

i had a totally different solution


2c2 is number of ways to select 2 black/white tv sets out of 2....
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Re: There are 8 TV sets, 6 are color and 2 are black-white. If 2 [#permalink]
SimaQ wrote:
Angela780 wrote:
conocieur wrote:
joemama142000 wrote:
There are 8 TV sets, 6 are color and 2 are black-white. If 2 sets are selected at random, what is the probability that at least one of them is color set?


1 - (2c2 / 8c2)

= 27/28


i'm going a lil crazy, but what is 2c2 again?? ..

i had a totally different solution


2c2 is number of ways to select 2 black/white tv sets out of 2....


ok Sima, please bear with me.. can you break the solution down step by step?
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Re: There are 8 TV sets, 6 are color and 2 are black-white. If 2 [#permalink]
OK....

First of all, to get the probability that at least one of the TV sets will be color we can use the following formula....

1-(the probability of choosing balck/white tv set both times)

To get that probability we have to calculate total favourable outcomes of choosing 2 black/white tv sets... which is 2c2 since we are calculating the number of ways to choose 2 tv sets out of 2....

... and divide it by the total number of possible outcomes... which is 8c2... since we have to choose 2 tv sets out of 8...

There may be other approaches, what approach did you use?
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Re: There are 8 TV sets, 6 are color and 2 are black-white. If 2 [#permalink]
P(at least 1 is color) = 1 - P(both are black-white) = 1 - (2/8)(1/7) = 27/78
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Re: There are 8 TV sets, 6 are color and 2 are black-white. If 2 [#permalink]
SimaQ wrote:
OK....

First of all, to get the probability that at least one of the TV sets will be color we can use the following formula....

1-(the probability of choosing balck/white tv set both times)

To get that probability we have to calculate total favourable outcomes of choosing 2 black/white tv sets... which is 2c2 since we are calculating the number of ways to choose 2 tv sets out of 2....

... and divide it by the total number of possible outcomes... which is 8c2... since we have to choose 2 tv sets out of 8...

There may be other approaches, what approach did you use?


my approach was this:

6 color tv..prob that 1 will be color 6/8, 2 black and white 2/7
6/8*2/7



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