Two men X and Y started working for a certain company at similar jobs

We are totaling 10 years of salary for each person, since X has an increase every year, we can group the monthly salaries into annual ones to have:

$3600 base salary, increased by $360 each year.

His salary for the last year would be \(3600 + 360*9\), the mean and median of each year's salaries would be \(\frac{3600 + 3600 + 360*9 }{ 2} = 3600 + 180*9 = 3600 + 1620 = 5220\). Finally multiply by 10 since that is the average for 10 years, to get \(52,200\).

For Y we repeat the same steps but we can consider 20 periods of 6 months, hence base salary 1200 with increments of 90.

At the end of 10 years his salary would be \(1200 + 90*19\). The mean and median of these 20 salaries would be \(\frac{1200 + 1200 + 90*19}{2}\). Multiply by 20 to get \(24000 + 900*19 = 24000 + 17100 = 41,100\).

Finally, add both salaries to get 93,300.

Ans: A