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Re: What do you think about this problem [#permalink]
:lol: Himalayan is absolutely correct - my bad. Sometimes I jump into the dark void that is math without turning on the flashlight. Please disregard my answer it's wrong.
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Re: What do you think about this problem [#permalink]
Himalayan wrote:
nick_sun wrote:
What do you think about this problem?


A.

statement 1 is suff. if n = (k+1)^3, n = (k+1)(k+1)(k+1) in which every term, (k+1), has reminder 1 if divided by k. therefore, all reminders have a product of 1. so suff.

statement 2 is not suff. k =5 but n could be any integers.


I've got it. Thank you, Himalayan!
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Re: What do you think about this problem [#permalink]
nick_sun wrote:
What do you think about this problem?


From statement 1 we have n= k^3+ 3k^2 + 3k +1. and we have to fine n/k. that is (k^3+ 3k^2 + 3k +1)/k that is equal to k^2 +3k +3 + 1/k . Also in the question stem it is given that k is >1 so the remainder of n/k is 1. So sufficient

Statement 2 says that k=5. But no information of n is given and hence this statement alone is insuficient.

Hence answere is A.

Javed.

Cheers!



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