Find all School-related info fast with the new School-Specific MBA Forum

It is currently 02 Aug 2015, 09:02
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

What is the area of the circle

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Director
Director
User avatar
Joined: 19 Mar 2007
Posts: 524
Followers: 3

Kudos [?]: 9 [0], given: 0

What is the area of the circle [#permalink] New post 09 Jul 2007, 03:50
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the area of the circle?

Last edited by nick_sun on 28 Jun 2008, 02:32, edited 1 time in total.
Senior Manager
Senior Manager
User avatar
Joined: 28 Feb 2007
Posts: 306
Followers: 1

Kudos [?]: 33 [0], given: 0

 [#permalink] New post 09 Jul 2007, 04:54
C.

Area of equilateral triangle S=[a^2*3^1/2]/4 so a=6

a- side of triangle. R- raduis of circumscribed circle.

R=a/(3^1/2) so R=2*3^1/2 and Pi*R^2=12*Pi.
Senior Manager
Senior Manager
avatar
Joined: 04 Jun 2007
Posts: 346
Followers: 1

Kudos [?]: 18 [0], given: 0

 [#permalink] New post 09 Jul 2007, 05:48
UMB wrote:
C.

Area of equilateral triangle S=[a^2*3^1/2]/4 so a=6

a- side of triangle. R- raduis of circumscribed circle.

R=a/(3^1/2) so R=2*3^1/2 and Pi*R^2=12*Pi.


That is right.

Radius of circumcircle = a/sqrt(3); a = side of triangle
Radius of incircle = [sqrt(3)*a]/6; a = side of triangle

These formulas are valid for equilateral triangles only! :-D
Senior Manager
Senior Manager
avatar
Joined: 11 Jun 2006
Posts: 254
Followers: 3

Kudos [?]: 5 [0], given: 0

 [#permalink] New post 09 Jul 2007, 06:17
Is there an easier way to do this? I would think the gmat doesn't want to test the forumula of a circumcircle.
Director
Director
User avatar
Joined: 19 Mar 2007
Posts: 524
Followers: 3

Kudos [?]: 9 [0], given: 0

 [#permalink] New post 09 Jul 2007, 06:44
UMB wrote:
R=a/(3^1/2) so R=2*3^1/2 and Pi*R^2=12*Pi.


Thank you, UMB! I've got it :P
  [#permalink] 09 Jul 2007, 06:44
Display posts from previous: Sort by

What is the area of the circle

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.