rovshan85 wrote:

what is the prob. of getting at least 2 heads in a row on three flips of a fair coin?

no answers are available, sorry

probability for HHT;

Total number of ways of arranging HHT keeping HH intact is 2!

probability = 2! * (1/2)^3

probability for HHH;

no of ways= 1

probability = (1/2)^3

hence required answer = 2! * (1/2)^3 + (1/2)^3

= 3* 1/8 = 3/8

Hope this helps...!!

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