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Re: An epidemic is reported to have broken out in Florida [#permalink]
SOLUTION
Solution: E


The key to solving this abstract problem is by recognizing that the number of newly detected instances must be an integer; you can’t have a fractional instance of a disease. If you define x as the number of instances last year and n as the number of new instances, then you know that \(n=\frac{85}{100}\).
After simplifying the fraction, this becomes \(n=\frac{17}{20}\) The smallest integer value that is possible for \(x\) is \(20\) so the smallest possible value for \(n\) is \(17\). Correct answer is (E).
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Re: An epidemic is reported to have broken out in Florida [#permalink]
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vomhorizon wrote:
An epidemic is reported to have broken out in Florida. The number of detected instances of a certain disease is reported to have increased by 85% in the last year. What is the lowest number of newly detected instances possible?

(A) 1

(B) 5

(C) 11

(D) 15

(E) 17


The key to this problem is realizing that we must have whole number values for both the original number of detected diseases and this year’s new number of cases. If we let the original number of detected diseases = n, then the new number of cases is:

1.85n = 185/100 x n = 37/20 x n = 37n/20

Since the fraction has been reduced to lowest terms, we see that for 37n/20 to be a whole number, then n must be at least 20.

Since 20 x 1.85 = 37, the minimum number of newly detected cases is 37 - 20 = 17 cases.

Answer: E
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Re: An epidemic is reported to have broken out in Florida [#permalink]
Can anyone give a descriptive and simple explanation to this question #less jargon
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An epidemic is reported to have broken out in Florida [#permalink]
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dipanjandas792 wrote:
Can anyone give a descriptive and simple explanation to this question #less jargon


An epidemic is reported to have broken out in Florida. The number of detected instances of a certain disease is reported to have increased by 85% in the last year. What is the lowest number of newly detected instances possible?

Assume initial deseases = x
increase in desease is 85% = x*185/100 = x*37/20

newly detected instances
= x*(37-20)/20
= x*(17/20)

Asked to find the lowest number of newly detected instances-
if x=20 then newly detected instances 17

if x is other than 20, we will either get decimal value or number of newly detected instances >17

so 17 -E is answer
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Re: An epidemic is reported to have broken out in Florida [#permalink]
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Re: An epidemic is reported to have broken out in Florida [#permalink]
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